Remove centroid locations of objects that are too close

2 ビュー (過去 30 日間)
Jason
Jason 2022 年 8 月 8 日
コメント済み: Jason 2022 年 8 月 9 日
Hi, I have a list of centroid locations of spots in an image (xf, yf). The spots are randomly distributed. I want to remove the centroid locations that are too close to each other, or say within a distance of d. I've got to the following but not sure what to do next. Also is there a better way to do this ratrher than use loops?
%using a loop
M=[];
for j=1:length(xf)
for i=1:length(xf)
dx=xf(j)-xf(i);
dy=yf(j)-yf(i);
dr=sqrt(power(dx,2)+power(dy,2));
M(j,1)=xf(j);
M(j,2)=yf(j);
M(j,3)=xf(i);
M(j,4)=yf(i);
M(j,5)=dr;
end
end
  2 件のコメント
Matt J
Matt J 2022 年 8 月 9 日
If two spots are less than d apart should both be removed? If not, by what criterion do you decide which spot remains?
Image Analyst
Image Analyst 2022 年 8 月 9 日
To me it sounds like both are to be removed. This is easily done with pdist2.

サインインしてコメントする。

採用された回答

Matt J
Matt J 2022 年 8 月 9 日
編集済み: Matt J 2022 年 8 月 9 日
A=[xf(:) yf(:)];
D=pdist2(A,A);
D(D==0)=inf; %retroactive EDIT
keep = all(D>d,1);
xf=xf(keep);
yf=yf(keep);
  7 件のコメント
Jason
Jason 2022 年 8 月 9 日
Of course, its clear now, thankyou
Jason
Jason 2022 年 8 月 9 日
Just to add, when I had over 400 objects, akthough i do other operations, using the for loop took 110s.using the pdist2 approach took just under 2s. Remarkable!

サインインしてコメントする。

その他の回答 (1 件)

yanqi liu
yanqi liu 2022 年 8 月 9 日
yes,sir,may be use pdist2, such as
xf = rand(1, 10);
yf = rand(1, 10);
%using a loop
M=[];
for j=1:length(xf)
for i=1:length(xf)
dx=xf(j)-xf(i);
dy=yf(j)-yf(i);
dr=sqrt(power(dx,2)+power(dy,2));
M(end+1,1)=xf(j);
M(end,2)=yf(j);
M(end,3)=xf(i);
M(end,4)=yf(i);
M(end,5)=dr;
end
end
% second method
A=[xf(:) yf(:)];
B=pdist2(A,A);
C=B';
C=C(:);
isequal(M(:,end),C)
ans = logical
1

カテゴリ

Help Center および File ExchangeTiming and presenting 2D and 3D stimuli についてさらに検索

製品


リリース

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by