How to interpolate a cloud of points?
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Francesco Pignatelli
2022 年 7 月 25 日
コメント済み: Francesco Pignatelli
2022 年 7 月 26 日
Hello all,
I have an set of 2D mean values from which I would like to compute the largest values. My 2D matrix is store so:
[rows, columns, count_there] = find(store == max(store));
By plotting rows vs columns I get the following picture:
I was wondering if there is any way to interpolate these data to get something like:
and to compute the length of it.
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Matt J
2022 年 7 月 25 日
編集済み: Matt J
2022 年 7 月 25 日
I've no way of testing this without your row/column data, but:
[rows, columns, count_there] = find(store == max(store));
[idx,edges]=discretize(columns,20);
edgectr=conv2(edges,[1,1]/2,'valid')';
G=findgroups(idx);
rowctr=splitapply(@median,rows,G);
colctr=splitapply(@(x) x(1),edgectr(idx),G);
scatter(rows,columns); hold on
plot(rowctr, colctr,'k-o','LineWidth',3); hold off
Length=sum(vecnorm(diff([rowctr(:),edgectr(:)]),2,2))
11 件のコメント
Matt J
2022 年 7 月 26 日
編集済み: Matt J
2022 年 7 月 26 日
This File Exchange file seems to do a decent job,
load store
[rows, columns, count_there] = find(store == max(store));
[idx,edges]=discretize(columns,20);
edgectr=conv2(edges,[1,1]/2,'valid')';
G=findgroups(idx);
rowctr=splitapply(@median,rows,G);
colctr=splitapply(@(x) x(1),edgectr(idx),G);
scatter(rows,columns); hold on
plot(rowctr, colctr,'k-o','LineWidth',3);
verticals=[600,700,800];
for i=1:numel(verticals)
[x0,y0]=intersections(rowctr,colctr,verticals(i)*[1,1],[0,1000]);
plot(x0,y0,'x--r');
valuesum(i)=sum(y0);
end; hold off
valuesum
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