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how to convert hours to 'yyyy-MM-dd hh:mm:ss' format?

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MP
MP 2022 年 7 月 15 日
コメント済み: Steven Lord 2022 年 7 月 15 日
I have time in hours from 0-72 hours (i.e. 0, 1, 2, 3,..., 72). i.e. a = 0:72;
I would like to convert this hours into datestr with 'yyyy-MM-dd hh:mm:ss' format.
I know initial yyyy-MM-dd i.e. 2012-04-24.
So how can i set my output in 'yyyy-MM-dd hh:mm:ss' format?
I want o/p to be like;
2012-04-24 00:00:00, 2012-04-24 01:00:00, ...., 2012-04-25 00:00:00, 2012-04-25 01:00:00, ...., 2012-04-26 00:00:00, 2012-04-26 01:00:00
date should change with each 24 hours.
Any help will be greatly appriciated.

採用された回答

Stephen23
Stephen23 2022 年 7 月 15 日
dtm = datetime(2012,4,24,'Format','yyyy-MM-dd HH:mm:ss') + hours(0:72).'
dtm = 73×1 datetime array
2012-04-24 00:00:00 2012-04-24 01:00:00 2012-04-24 02:00:00 2012-04-24 03:00:00 2012-04-24 04:00:00 2012-04-24 05:00:00 2012-04-24 06:00:00 2012-04-24 07:00:00 2012-04-24 08:00:00 2012-04-24 09:00:00 2012-04-24 10:00:00 2012-04-24 11:00:00 2012-04-24 12:00:00 2012-04-24 13:00:00 2012-04-24 14:00:00 2012-04-24 15:00:00 2012-04-24 16:00:00 2012-04-24 17:00:00 2012-04-24 18:00:00 2012-04-24 19:00:00 2012-04-24 20:00:00 2012-04-24 21:00:00 2012-04-24 22:00:00 2012-04-24 23:00:00 2012-04-25 00:00:00 2012-04-25 01:00:00 2012-04-25 02:00:00 2012-04-25 03:00:00 2012-04-25 04:00:00 2012-04-25 05:00:00
  4 件のコメント
Stephen23
Stephen23 2022 年 7 月 15 日
編集済み: Stephen23 2022 年 7 月 15 日
str = string(dtm) % string array
txt = cellstr(dtm) % cell array of character vectors
Steven Lord
Steven Lord 2022 年 7 月 15 日
I want to put xticklabels.
If you're plotting using this datetime data as one of the inputs in your call to plot, the tick labels will automatically be generated from the plotted datetime array. You don't need to convert to a string array in this case.
v = 0:10;
x = datetime('today') + days(v);
y = v.^2;
plot(x, y)

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その他の回答 (1 件)

MP
MP 2022 年 7 月 15 日
Yes, that did a great help.... :)
Thank you so much @Stephen23

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