Need a fix for interp1 error

4 ビュー (過去 30 日間)
Chris Swain-Phipps
Chris Swain-Phipps 2022 年 6 月 27 日
コメント済み: Chris Swain-Phipps 2022 年 6 月 27 日
Hi,
I am trying to use interp1() function on some input data to increase the number of data points I have available to perform more precise checks, my input data is stated to 5 d.p. but ocassionally adjacent values can be identical (i.e. 0.00007, 0.00026, 0.00041, 0.00041, 0.00057...).
Any thoughts on how I still use the interp1 function without my script crashing when identical values are present?
Many Thanks,
Chris

採用された回答

dpb
dpb 2022 年 6 月 27 日
The simplest is to use
[ux,ia]=unique(x);
vi=interp1(ux,y(ia),v);
This will use the first of the y values for each unique x; you could get more sophisticated and find those values and average them or otherwise set the interpolant value at that value.
Alternatively, I have on occasion found the duplicate locations and adjusted their positions by ux+/-2*eps(ux) to make them just far enough apart that interp1 doesn't complain. This is useful if there is a real discontinuity in the interpolant at the point and it is desired to model it as well.
  1 件のコメント
Chris Swain-Phipps
Chris Swain-Phipps 2022 年 6 月 27 日
Yep, that did the trick.
Cheers!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeInterpolation についてさらに検索

タグ

製品


リリース

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by