I want to calculate the RMS, MEAN, STD of the first three elements of any predefine array and store it in new array and then calculate the same for the next three elements

7 ビュー (過去 30 日間)
Rajeev Kumar
Rajeev Kumar 2022 年 6 月 9 日
編集済み: dpb 2022 年 6 月 10 日
I want to calculate the RMS, MEAN, STD of the first three elements of any predefine array and store it in new array and then calculate the same for the next three elements and store it in the same new array and so on till last.

回答 (1 件)

dpb
dpb 2022 年 6 月 9 日
編集済み: dpb 2022 年 6 月 9 日
N=size(x,1); % number rows in x
g=kron([1:N/3].',ones(3,1)); % grouping variable by three
[gmean,gstd,grms]=grpstats(x,g,{'mean','std',@rms})); % compute
See grpstats for all the details of possible ways to organize output.
NB: the above requires N be an even multiple of 3
  2 件のコメント
Rajeev Kumar
Rajeev Kumar 2022 年 6 月 10 日
Please make changes in my code with reference to the above query
clear all
clc
B=[1,20,50,11,15,56,15,58,45,47,65,42,67,98,53,48,47,78,65,25];
A=[];
D=[];
% mean=0;
count=1;
l=length(B);
for i=1:l
mean=std(B);
if count ==3
A=[A,mean];
mean=0;
end
if count == 3
count=1;
else
count=count+1;
end
disp(A);
end
dpb
dpb 2022 年 6 月 10 日
編集済み: dpb 2022 年 6 月 10 日
Use "the MATLAB way" I showed you instead.
"x" is your "predefined array"; simply use your variable name. You'll want to add error checking or otherwise handle the case of other than a multiple of three records if it is ever possible that condition can arise; we don't have sufficient information to know about edge case.
You can use/rearrange the returned statistics arrays with whatever variable structure/names you wish for the end result, but compute the results efficiently with grouping a variable.
mean=std(B);
Don't use mean as a variable; it's the builtin function for the statistic; doing this will create all sorts of unexpected havoc.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeNaNs についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by