How to find closest values within a matirx
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Hi have a matirx
[NAN NAN NAN 7 8 9;
NAN NAN 5 7 8 7;
4 8 6 8 3 4;
4 7 0 1 1 4]
How do I replace the NAN values with the closest values known values. So the matirx will kind of look like
[4 5 7 7 8 9;
4 8 5 7 8 7;
4 8 6 8 3 4;
4 7 0 1 1 4]
4 件のコメント
Steven Lord
2022 年 4 月 29 日
What are your rules for "closest"? For element (1, 3) you fill in the NaN with the value from (1, 4) rather than the value from (2, 3). But for element (2, 2) you fill in with the value from (3, 2) rather than the value from (2, 3). Why do you choose the element to the side in the first case but the element below in the second?
採用された回答
Matt J
2022 年 4 月 29 日
A=[nan(1,3) 7 8 9;
nan(1,2) 5 7 8 7;
4 8 6 8 3 4;
4 7 0 1 1 4]
nanmap=isnan(A);
[~,idx]=bwdist(~nanmap);
A(nanmap)=A(idx(nanmap))
その他の回答 (1 件)
DGM
2022 年 4 月 29 日
編集済み: DGM
2022 年 4 月 29 日
I'm not really sure what you mean by "closest values". Maybe you're talking about inpainting?
A = [NaN NaN NaN 7 8 9;
NaN NaN 5 7 8 7;
4 8 6 8 3 4;
4 7 0 1 1 4]
B = regionfill(A,isnan(A))
If you don't have regionfill() (Image Processing Toolbox), you can always use John's inpaint_nans() on the File Exchange
C = inpaint_nans(A)
You might also be able to use fillmissing() depending on the directional behavior you intend.
2 件のコメント
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