フィルターのクリア

Split an Array in sub-arrays based on the first number in the column

3 ビュー (過去 30 日間)
Fabio Taccaliti
Fabio Taccaliti 2022 年 4 月 19 日
コメント済み: Stephen23 2022 年 4 月 20 日
Hello,
I have an array M 2939x4 that I would like to split in sub-arrays based on the number in the first column.
I mean in the first colunm a number is listed, first 0, then 0.02, then 0.04 and so on (with an increment of 0.02) until 2.2, the problem is that the times that this number appear is not always the same (for example the 0 is on the first 28 rows, the 0.02 in the following 24 and the 0.04 in the next 29).
My idea was to find the number of different number listed in the first column (time) and how many times they occurs (b).
[time,b] = unique(M(:,1));
b = [b; length(M)];
How can I continue it?
Thanks in advance.

採用された回答

Stephen23
Stephen23 2022 年 4 月 19 日
M = [[0;0.2;0.2;0.4;0.6;0.6;0.6],rand(7,3)]
M = 7×4
0 0.4950 0.3418 0.1799 0.2000 0.7419 0.8047 0.6176 0.2000 0.0316 0.7905 0.7259 0.4000 0.0520 0.9471 0.8603 0.6000 0.2431 0.9200 0.8624 0.6000 0.2946 0.9786 0.6720 0.6000 0.1605 0.0039 0.7209
D = diff(find([1;diff(M(:,1));1]));
C = mat2cell(M,D,4)
C = 4×1 cell array
{[ 0 0.4950 0.3418 0.1799]} {2×4 double } {[0.4000 0.0520 0.9471 0.8603]} {3×4 double }
C{:}
ans = 1×4
0 0.4950 0.3418 0.1799
ans = 2×4
0.2000 0.7419 0.8047 0.6176 0.2000 0.0316 0.7905 0.7259
ans = 1×4
0.4000 0.0520 0.9471 0.8603
ans = 3×4
0.6000 0.2431 0.9200 0.8624 0.6000 0.2946 0.9786 0.6720 0.6000 0.1605 0.0039 0.7209
  3 件のコメント
Fabio Taccaliti
Fabio Taccaliti 2022 年 4 月 19 日
編集済み: Fabio Taccaliti 2022 年 4 月 19 日
What about if I want to plot each last 3 columns of the sub-arrays? column 2 is the x-cooediante, column 3 the y and column 4 the z.
figure(1)
for i = length(C)
hold on; grid on; grid minor; axis equal;
scatter3(C{i}(:,2),C{i}(:,3),C{i}(:,4))
view(3)
xlabel('x [mm]')
ylabel('y [mm]')
zlabel('z [mm]')
end
Something like this, but this plot just the first one
Stephen23
Stephen23 2022 年 4 月 20 日
for i = 1:numel(C)
^^

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeArray Geometries and Analysis についてさらに検索

タグ

製品


リリース

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by