フィルターのクリア

sum of product of 2 matrices

3 ビュー (過去 30 日間)
Sreejith
Sreejith 2015 年 1 月 10 日
編集済み: John D'Errico 2015 年 1 月 10 日
hi
i have 2 matrices... u is a 2 x 1250 matrix and r is a 1250 x 1250 matrix...
here c = 1
for each j = 1 to 1250 i want to find
how to writ the matlab code for this ?

回答 (2 件)

Zoltán Csáti
Zoltán Csáti 2015 年 1 月 10 日
It is just a standard matrix-matrix product: u*r. So enter
value = u(1,:)*r;
The j-th column of the matrix "value" will contain the sum for the specific j.
  4 件のコメント
Zoltán Csáti
Zoltán Csáti 2015 年 1 月 10 日
This is what my code does. Write a few indices and you will see.
John D'Errico
John D'Errico 2015 年 1 月 10 日
編集済み: John D'Errico 2015 年 1 月 10 日
+1. What you don't seem to understand is that the * operator IS a dot product, i.e., the sum of products of elements. After all, MATLAB is a matrix language, so it is written to do these computations trivially, with the basic operators.
You sum of products is simply a dot product, what * delivers.

サインインしてコメントする。


Guillaume
Guillaume 2015 年 1 月 10 日
Use bsxfun:
sum(bsxfun(@times, u(c, :)', r))
  3 件のコメント
Zoltán Csáti
Zoltán Csáti 2015 年 1 月 10 日
Guillaume provided a vectorized version, that's why there is no matrix index j.
Guillaume
Guillaume 2015 年 1 月 10 日
bsxfun replicates u(c,:)' for each column j of r and sum calculates the sum for each of these columns. Exactly what you asked for.
Just try my code without any modification.
Note, this is equivalent to:
tempu = repmat(u(c, :)', 1, size(r, 2));
p = tempu .* r;
result = sum(p)
Or, if you really want to introduce j and make the calculation much slower:
tempu = repmat(u(c, :)', 1, size(r, 2));
p = tempu .* r;
result = zeros(1, size(r, 2));
for j = 1:size(r, 2)
result(j) = sum(p(:, j));
end
The one line bsxfun does the same.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeMatrix Indexing についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by