Eigenvectors of a 3D eigenvalue matrices

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Pseudoscientist
Pseudoscientist 2022 年 3 月 18 日
コメント済み: Christine Tobler 2023 年 10 月 11 日
I have three matrices called Lambda1, Lambda2 and Lambda3. The size of each matrix is 512x512x220. Lambda1 contains eigenvalues λ1 for each x, y and z, Lambda2 contains eigenvalues λ2 for each x, y and z and Lambda3 contains eigenvalues λ3 for each x, y and z.
How do I calculate eigenvectors for every x, y and z of the 512x512x220 matrix?
  2 件のコメント
Matt J
Matt J 2022 年 3 月 18 日
You cannot calculate eigenvectors knowing only the eigenvalues and nothing else. You need the matrix that the eigenvalues came from.
Pseudoscientist
Pseudoscientist 2022 年 3 月 18 日
Oh alright, I have that too. It is called V.

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回答 (1 件)

Jaswanth
Jaswanth 2023 年 10 月 11 日
Hi Pseudoscientist,
Considering that you have the values of the mentioned three matrices, Lambda1, Lambda2, and Lambda3, each containing eigenvalues for each x, y, and z coordinate, you can create eigenvectors using the "eig" function.
Please refer the following sample code:
% Create Eigenvalues matrix
% The diag() function is used to create a diagonal matrix with these eigenvalues as its diagonal elements.
Eigenvalues = diag([lambda1, lambda2, lambda3]);
% Solve eigenvalue problem
[V, ~] = eig(Eigenvalues);
For more information on the functions used here, please refer to the following resources:
  1. “eig”: https://in.mathworks.com/help/matlab/ref/eig.html
  2. “diag”: https://in.mathworks.com/help/matlab/ref/diag.html?searchHighlight=diag&s_tid=srchtitle_support_results_1_diag
Hope this Helps.
  1 件のコメント
Christine Tobler
Christine Tobler 2023 年 10 月 11 日
As Matt J. said above, it's not possible to compute the eigenvectors given only the eigenvalues. Here you are simply constructing a new matrix, for which the eigenvectors can be computed, but they won't match the eigenvectors of the original matrix (in fact, V will just be the identity matrix here).

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