Fitting a function: constraining a parameter to be 0 or 1?

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Greg
Greg 2014 年 12 月 12 日
回答済み: Matt J 2014 年 12 月 12 日
I have two variables of the same length, e.g. x and y. I want to find the parameters for function f such that y = f(x). Functions like lsqcurvefit let me bound the parameters, but is there any way to constrain a parameter to be an integer?
Specifically I have a parameter that I want to constrain to be either 0 or 1. Is there a way to do this? Any help would be lovely.

回答 (1 件)

Matt J
Matt J 2014 年 12 月 12 日
Probably not applicable to (or too complicated for) this problem, but if f(x) has a linear dependence on the unknowns,
y=p1*f1(x)+p2*f2(x)+...+pn*fn(x)
where p1...pn are the unknown parameters, some of which are integers, then instead of doing a least squares fit, you can do a max-norm fit
min r
subject to
-r<=y-( p1*f1(x)+p2*f2(x)+...+pn*fn(x) )<=r
which is a mixed integer linear program in the variables [r,p1,...,p3] and can be solved with intlinprog . An L1-norm fit can be done in a similar way.

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