How to fprintf a transposed matrix?

Hello, I am trying to use fprintf to show the values of a transposed matrix. However, it does not seem to show the values as I would hope.

A = [7 11; 15 23; 9 7];

T=A.';

fprintf('\n A''= \n');

fprintf(' %d \t %d \t %d\n',T);

The result will be;

7 11 15

23 9 7

But I am expecting;

7 15 9

11 23 7

Answer 1

[Stephen23]

fprintf(..,T.');
%           ^^

Or skip T entirely:

fprintf(..,A);

In MATLAB, just like in many other mathematical computation languages (e.g. FORTRAN), array elements are stored going down the rows first, then along the columns, etc.

https://www.mathworks.com/help/coder/ug/what-are-column-major-and-row-major-representation-1.html

When you process data in linear order (e.g. as FPRINTF does), you always need to take into account the order that the data are actually stored in memory.

[Anthony Sullivan]

Thank you! Didn't realize the original transpose wouldn't carry over

Answer 2

[Jan]

fprintf takes the argument elementwise as they are store in the memory. So:

A = [7 11; 15 23; 9 7];
fprintf(' %d \t %d \t %d\n', T);

is equivalent to:

fprintf(' %d \t %d \t %d\n', T(:));

Transposing the matrix is the solution, as Stephen has answered already.