# How to break with two conditions

3 ビュー (過去 30 日間)
Moe 2014 年 11 月 26 日
コメント済み: Adam 2014 年 12 月 1 日
I want to break my code
when both m and m2m is smaller than 0
I used the following command, but it gave me error:
if m(:,:,j) < 0 AND m2m(:,:,j) < 0
break % get out of the for-loop
end
% Undefined function 'AND' for input arguments of type 'char'.
% Error in new55 (line 340)
if m(:,:,j) < 0 AND
m2m(:,:,j) < 0
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Star Strider 2014 年 12 月 1 日
Thank you!

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### 回答 (2 件)

Image Analyst 2014 年 11 月 26 日
m(:,:,j) and m2(:,:,j) are not single numbers. They're 2D arrays. I suggest you wrap them in any() or all(), depending on what you're wanting - any element to meet the criteria or all of the elements in the 2D matrix to meet the criteria. Plus use && instead of AND:
if all(m(:,:,j)) < 0 && all(m2m(:,:,j)) < 0
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Adam 2014 年 12 月 1 日
Yeah, I guess a squeeze may be needed and maybe an all( all( ... ) ).
I created functions called
column(x)
row(x)
in our Matlab library that just warp up the functionality for making a matrix a column ( i.e. the (:) notation ) and a row (transpose of column notation) so that I can use them in situations like this because Matlab does not allow syntax like:
m(:,:,j)(:)
which is what you'd need to do to achieve the same thing in non-function syntax.

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Andrew Reibold 2014 年 11 月 26 日
if m(:,:,j) < 0 && m2m(:,:,j) < 0
'AND' will not work. Make that change and start debugging from there.
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Stephen 2014 年 12 月 1 日
As Image Analyst points out " m(:,:,j) and m2(:,:,j) are not single numbers. They're 2D arrays", so the scalar operator && will not work like that. These arrays need to be wrapped in an all or any (or something similar) before applying the && operator:
if all(m(:,:,j) < 0 ) && all(m2m(:,:,j) < 0 )

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