Are there two conditions at once when using the if condition?

Hello. I have a question and am posting.

I solved it as below, but the value I want is not found, so I ask. Q_1 is entered only when tact is 1 and k is 1, and I am trying to calculate the rest by putting the rest in the expression.

So, when tact is 1 and k is 1, can't we just put the value of Q_1?? For the rest, I try to use the formula below.​

​

Q_1 = 30;

Q_D = 11.3;

Q_E = 8.3;

Q_R = 7.5;

Q_F = 4.5;

connection_D = [1,0,0,0; 0,1,0,0; 0,0,1,0; 0,0,0,1];

connection_E = [0,1,0,0; 0,0,1,0; 0,0,0,1; 1,0,0,0];

connection_F = [0,0,1,0; 0,0,0,1; 1,0,0,0; 0,1,0,0];

connection_R = [0,0,0,1; 1,0,0,0; 0,1,0,0; 0,0,1,0];

​

for tact = 1:4

for k=1:4

if k==1

Q_column(1)=Q_1

else

Q_column(k) = Q_column(k-1) + Q_D*connection_D(tact,k) - Q_E*connection_E(tact,k) + Q_F*connection_F(tact,k) - Q_R*connection_R(tact,k)

end

end

end

[Stephen23]

I suspect that you want this:

if k==1 && tact=1

Answer 1

[Prince Kumar]

Hi,

You can use logical operator & to achieve this.

Q_1 = 30;
Q_D = 11.3; 
Q_E = 8.3; 
Q_R = 7.5; 
Q_F = 4.5;  
connection_D = [1,0,0,0; 0,1,0,0; 0,0,1,0; 0,0,0,1];
connection_E = [0,1,0,0; 0,0,1,0; 0,0,0,1; 1,0,0,0];
connection_F = [0,0,1,0; 0,0,0,1; 1,0,0,0; 0,1,0,0];
connection_R = [0,0,0,1; 1,0,0,0; 0,1,0,0; 0,0,1,0];
​
for tact = 1:4
    for k=1:4
    if k==1 & tact == 1 
        Q_column(1)=Q_1
        else
        Q_column(k) = Q_column(k-1) + Q_D*connection_D(tact,k) - Q_E*connection_E(tact,k) + Q_F*connection_F(tact,k) - Q_R*connection_R(tact,k)
    end
    end
end

You can use any combination of operators as per your need.

Hope this helps.