Hi, is it possible to have variables in an ode45 that varies according to another function?

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Rachel Ong
Rachel Ong 2022 年 1 月 12 日
コメント済み: Stephen23 2022 年 1 月 12 日
This is my ode45 that I have to solve and, actually, the variables rho and speedsound (i have commented them out in the first script) is supposed to vary with altitude (x(1)). How do I allow this to work if I have another function called atmos and I want it to go back to atmos to retrieve the values of rho and speed sound for ever altitude it is before the next time step of integration?
%% Dynamic equations to do ODE45
function xdot = dynameqn(t,x,eledefl, thrustvec)
xdot = zeros(1,7);
g = 9.81;
c = 1.74;
S = 17.1;
initial_mass = 1248.5;
Ix = 1421;
Iy = 4067.5;
Iz = 4786;
Ixz = 200;
thrust_sfc = 200/60/60/1000; %kg/kN/h --> kg/N/s --> /60^2 & /1000
% rho = 1.225;
% speedsound = 340.26;
powersetting = 4;
height = x(1);
horz_displacement = x(2);
alpha = x(3);
u = x(4);
q = x(5);
theta = x(6);
mass = x(7);
CL = 6.44*alpha + 3.8*c*q/(2*u) + 0.355*eledefl; % lift coefficient
L = 0.5*rho*u^2 * CL * S; % lift force
CD = 0.03 + 0.05*CL^2; % drag coefficient
D = 0.5*rho*u^2 * CD* S; % drag force
Cm = 0.05 - 0.683*alpha - 9.96*c*q/(2*u) - 0.923*eledefl; % pitching moment coefficient
m = 0.5*rho*u^2*S*c*Cm; % pitching moment
thrust = powersetting * ( (7+u/speedsound)*200/3 + height/1000*(2*u/speedsound -11) ); % thrust force
xdot(1) = u*sin(theta-alpha); % h'= rate of vertical climb
xdot(2) = u*cos(theta-alpha); % x'= rate of change of horizontal displacement
xdot(3) = q - (thrust*sin(alpha+thrustvec) + L) / (mass* u) + g/u*cos(theta - alpha); % alpha'
xdot(4) = (thrust * cos(alpha+thrustvec) - D)/ mass - g*sin(theta-alpha); % u'
xdot(5) = m/Iy; % q'
xdot(6) = q; % theta'
xdot(7) = -thrust_sfc * thrust; % mass'
xdot=xdot';
end
atmos script below:
% Calculating T, p ,rho and speedsound for every altitude in the ISA atmosphere
function [rho, speedsound] = atmos_ode45(h)
h1 = 11; % Height of tropopause
h2 = 20; % End height of table
g = 9.81;
R = 287;
c = 6.51e-3; % temperature lapse dt/dh = - c = -6.51 degcelcius/km
T0 = 15+273.15; % Temperature sea level
p0 = 101325; % pressure sealevel
rho0 = 101325/R/T0; % density sealevel = pressure / R*T, R=287, T = 15 degcelcius
T1 = T0 - c*h1*1000; % Temperature at 11km
p1 = p0 * (T1/T0)^5.2506; % Pressure at 11km
rho1 = rho0 * (T1/T0)^4.2506; % Density at 11km
T2 = T1; % Temperature at 20km
p2 = p1 * exp(-g/(R*T2)*(h2-h1)*1000); % Pressure at 20km
rho2 = rho1 * exp(-g/(R*T2)*(h2-h1)*1000); % Density at 20km
if h <= h1
% disp('Troposphere');
T = T0 - c*h*1000
p = p0 * (T/T0)^5.2506
rho = rho0 * (T/T0)^4.2506
speedsound = (1.4*R*T)^0.5
elseif h <= h2
% disp('Tropopause');
T = T1
p = p1 * exp(-g/(R*T)*(h-h1)*1000)
rho = rho1 * exp(-g/(R*T)*(h-h1)*1000)
speedsound = (1.4*R*T)^0.5
end
return
end

回答 (1 件)

Alan Stevens
Alan Stevens 2022 年 1 月 12 日
Put something like
[T, p, rho, speedsound] = atmos(height);
immediately after
height = x(1);
in function dynameqn.
Not sure why you return T and p from atmos, as you don't seem to use them in dynameqn. Perhaps you use them elsewhere.
  7 件のコメント
Torsten
Torsten 2022 年 1 月 12 日
If this is unphysical, you should check your equations for errors.
Stephen23
Stephen23 2022 年 1 月 12 日
"Do you happen to have any idea how I can fix this? "
Make sure that continuous values are defined for all h.

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