Matlab unable to format string to path

In original script there is part of code where is this

filepathsource='C:\Users\...';
strFP=dir([filepathsource '*.txt']);

Which works nicely. Problem is that i need to change that filepathsource to some more dynamic so i did.

filepathsource=string(strcat(app.folderPath,'\',string(app.currentCount),'\'));
strFP=dir([filepathsource '
    *.txt']);

But i end with error

Error using dir

Name must be a text scalar.

And i need original formating because i get errors later in script. Is there any way how can i fix it? I tried everything but always is something somewhere wrong. And i just dont understand whats difference between original filepathsource and the one that i created bot are strings. (output of my filepathsource is correct when i display it)

[Stephen23]

" Is there any way how can i fix it? "

Yes: use FULLFILE instead of concatenating strings and separators.

Answer 1

[Walter Roberson]

Use fullfile() instead of concatenation of characters or strings.

Your most immediate problem is that the results of

['characters' "string"]

is not 'charactersstring' or "charactersstring" and is instead ["characters" "string"] -- that is, [] between a character vector and a string is done by converting the character vector into a string object and then you have [] of two string objects which gives you a string array.

To join a character vector and a string object use strjoin() or use the + operator such as 'hello' + "there"

But all this is best avoided by using fullfile()