plugging in a function inside fittype, error

9 ビュー (過去 30 日間)
Alvaro Sanchez
Alvaro Sanchez 2021 年 12 月 10 日
回答済み: Walter Roberson 2021 年 12 月 22 日
Hello. I'm new in matlab. I'm currently trying to use the fittype function to later on use to fit.
I have a truncated exponetial whcih i define in the following matlab function.
function [yf] = Exp_t(x3,a,m)
%x and y data are arrays with size 20x1
%a and m are unknown coeficients to be fitted.
for i=1:20
if x3(i)<0 %truncation
yf(i,1)=0;
elseif (x3(i)>=0) && (x3(i)<=a)
yf(i,1)=(1-exp(-m*x3(i)))/(1-exp(-m*a)); %exponential fucntion
elseif x3(i)>a %truncation
yf(i,1)=1;
end
end
end
I then insaert this function in my main script
%truncated exponential fit.
y3=(table1{:,4}); %data from column 4 table1
x3=(table1{:,3}); %data from column 3 table1
%inserting Exp_t(x3,a,m) into fittype function
ft = fittype( 'Exp_t(x3,a,m)','independent', {'x3'}, 'dependent', {'yf'},'coeff',{'a','m'});
%fit(x3,y3,ft,'Robust','on')
I've spent more than two days trying to fix this, any help is much apreciated.
I receive the following errors:
Error using fittype/testCustomModelEvaluation (line 12)
Expression Exp_t(x3,a,m) is not a valid MATLAB expression, has non-scalar coefficients, or cannot be evaluated:
Error in fittype expression ==> Exp_t(x3,a,m)
??? Index exceeds the number of array elements (7).
Error in fittype>iCreateFittype (line 373)
testCustomModelEvaluation( obj );
Error in fittype (line 330)
obj = iCreateFittype( obj, varargin{:} );
Error in Project_2 (line 105)
ft = fittype( 'Exp_t(x3,a,m)','independent', {'x3'}, 'dependent', {'yf'},'coeff',{'a','m'});
Caused by:
Error using fittype/evaluate>I_ERROR_FCN_ (line 179)
Error in fittype expression ==> Exp_t(x3,a,m)
??? Index exceeds the number of array elements (7).

採用された回答

Gargi Patil
Gargi Patil 2021 年 12 月 21 日
Hi,
This error can be resolved by declaring the size of the output array yf beforehand in the function Exp_t as follows:
function [yf] = Exp_t(x3, a, m)
%x and y data are arrays with size 20x1
%a and m are unknown coeficients to be fitted.
yf = zeros(size(x3, 1), 1);
....
end
  2 件のコメント
Alvaro Sanchez
Alvaro Sanchez 2021 年 12 月 21 日
thanks, that worked but also had to remove the brackets.
Matt J
Matt J 2021 年 12 月 22 日
@Alvaro Sanchez If it worked, please Accept-click the answer.

サインインしてコメントする。

その他の回答 (1 件)

Walter Roberson
Walter Roberson 2021 年 12 月 22 日
ft = fittype( 'Exp_t(x3,a,m)','independent', {'x3'}, 'dependent', {'yf'},'coeff',{'a','m'});
Instead of using a quoted character expression, use an anonymous function.

カテゴリ

Help Center および File ExchangeLinear and Nonlinear Regression についてさらに検索

製品


リリース

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by