I have a plot that gives me the following plot.
plot(field0(:,1), field0(:,2))
xlim([-0.1 0.02])
Is it possible to convert this to 3D plot that will look something like this?

6 件のコメント

Rik
Rik 2021 年 12 月 8 日
Of course you can, but how do you want to determine the other lines to be plotted from your single line? Is all the data in field0?
Vahram Voskerchyan
Vahram Voskerchyan 2021 年 12 月 8 日
yes, that's the problem all data is in field0.
Matt J
Matt J 2021 年 12 月 8 日
That's not the problem. It's a part of the problem definition. You must select one of the infinite possible 3D extensions that you want and tell us what it is.
Vahram Voskerchyan
Vahram Voskerchyan 2021 年 12 月 8 日
the idea is to somehow rotate the plot taking the peak point as the center and have a 3D plot.
Rik
Rik 2021 年 12 月 8 日
In that case you must first try to find the peak point and decide how exactly you want to rotate. Do you want to make it symetrical? The plot you showed isn't symetrical itself, so how should the code deal with that?
Vahram Voskerchyan
Vahram Voskerchyan 2021 年 12 月 8 日
I want to rotate it clockwaise with the shape it has.

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 採用された回答

Matt J
Matt J 2021 年 12 月 8 日
編集済み: Matt J 2021 年 12 月 8 日

0 投票

You must select one of the infinite possible 3D extensions that you want and tell us what it is.
One possibility:
load field0
x=field0(:,1);
idx=abs(x)<0.08;
[x,y,z]=deal(x(idx),x(idx),field0(idx,2));
surf(x,y,z*z.','MeshStyle','row'); view(10,60)

1 件のコメント

Vahram Voskerchyan
Vahram Voskerchyan 2021 年 12 月 9 日
thanks a lot for your answer! didn't know about the deal command.

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その他の回答 (1 件)

DIVYA K
DIVYA K 2022 年 8 月 10 日

0 投票

is there chance to do this line graph into 3D graph

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2021 年 12 月 8 日

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2022 年 8 月 10 日

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