How to use a function within optiproblem?
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My minimization function is:
pi = x(1)+x(2)-rho*min(0,x(1)^2+x(2)^2
how can i use this equation in optimproblem?
prob = optimproblem("Objective",x(1)+x(2)-rho*min(0,x(1)^2+x(2)^2),"ObjectiveSense","minimize");
x0.x = [0;0];
Error using min
Invalid data type. Second argument must be numeric or logical.
1 件のコメント
Matt J
2021 年 12 月 1 日
Note that min(0,x(1)^2+x(2)^2) will always be 0, so it is not contributing anything to the objective function.
回答 (1 件)
Akshat Dalal
2024 年 4 月 18 日
Hi Anthony,
The error you're encountering is due to the way "min" function is being used within the "optimproblem" context. The "min" function expects its arguments to be numeric or logical arrays, but when defining an optimization problem symbolically, you're dealing with symbolic expressions or optimization variables, which are not directly compatible within MATLAB functions such as the "min" function.
However, as Matt already mentioned, your minimization function is independent of the "min" function as the second argument is a sum of two square numbers which is always greater than or equal to zero. Thus your function can be reduced to "x(1)+x(2)" which should work with as desired.
Hope this helps!
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