How to apply an equation to each element in the array?

5 ビュー (過去 30 日間)
KarolN
KarolN 2021 年 11 月 27 日
コメント済み: KarolN 2021 年 11 月 28 日
I have an equation:
Which I need to apply to every element in a 10x10 matrix of u.
u - a node in numerical model of rock layer
j,n - indexes of movement
The matrix is supposed to have identical starting values of 80.

採用された回答

Matt J
Matt J 2021 年 11 月 27 日
conv( u , [0 1 0]+alpha*[1 -2 1] )
  5 件のコメント
Matt J
Matt J 2021 年 11 月 28 日
Use conv2 instead
soilSub = conv2( u, [0 1 0]+alpha*[1 -2 1] )
KarolN
KarolN 2021 年 11 月 28 日
IT WORKS! Thank you very much for your valuable advice!

サインインしてコメントする。

その他の回答 (1 件)

Image Analyst
Image Analyst 2021 年 11 月 28 日
Try conv2():
k = 10^-7 % filtration of soil
M = 19000
q = 80 % external force Q acting on soil
DeltaZ = 0.1 % depth of soil subsidization
GammaW = 10 % water weight [Kn/m^3]
Cv = k*M/GammaW % consolidation factor
DeltaT = DeltaZ^2/(2*Cv) % max iteration step
alpha = Cv*DeltaT/DeltaZ^2
% NUMERICAL PARAMETERS
u = q*ones(10:10) % matrix of u nodes
% SOLUTION
kernel = [0, 1, 0] + alpha * [1, -2, 1]
% Discrete form of the governing equation:
soilSub = conv2(u, kernel) % Use conv2(), not conv()
  4 件のコメント
Image Analyst
Image Analyst 2021 年 11 月 28 日
No problem. I'm sure using conv() instead of conv2() was just an oversight by Matt. I know he knows better - he's a bright guy. You can vote for multiple answers though you can only Accept one. You can even vote for one you Accepted to award double the reputation points to that one.
KarolN
KarolN 2021 年 11 月 28 日
And so additionally I learned about that vote feat :) Voted for both of you naturally. Thanks guys

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeProgramming についてさらに検索

製品


リリース

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by