Problem with parfor with two variables
1 回表示 (過去 30 日間)
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Hi,
My code below is executed normally without the parfor command i.e with the for command.
Moreover when I reduce the numbre of cores to 4 in parfor command, the code run normally, it will be displayed on the screen ('Time to calculate the (i,j)th couple is ....) but if I use all the 32 cores I didn't see anything in my screen after 24h of the execute my code.
Can you help me this is urgent.
Thank you for our help.
%% My code
Y_1 =zeros(N,numel(alpha),numel(beta));
Y_2 =zeros(N,numel(alpha),numel(beta));
parfor k =1:numel(alpha)*numel(beta)
Tm=tic;
[i,j]=ind2sub([numel(alpha),numel(beta)],k);
[Y_1(:,k),Y_2(:,k)] = My_Fun(alpha(i),beta(j),..);
fprintf('Time to calculate the (%d,%d)th couple is %f \n',i,j,toc(Tm))
end
4 件のコメント
Edric Ellis
2021 年 11 月 24 日
I would check the memory usage on your system. It may be that when using 32 cores, you're overwhelming the system memory and things are running extremely slowly.
回答 (1 件)
Matt J
2021 年 11 月 24 日
編集済み: Matt J
2021 年 11 月 24 日
Do you need to see the toc output in real time? If not, just save it until later:
%% My code
Y_1 =nan(N,numel(alpha),numel(beta));
Y_2 =nan(N,numel(alpha),numel(beta));
Times=nan(numel(alpha), numel(beta));
parfor k =1:numel(alpha)*numel(beta)
Tm=tic;
[i,j]=ind2sub([numel(alpha),numel(beta)],k);
[Y_1(:,k),Y_2(:,k)] = My_Fun(alpha(i),beta(j),..);
Times(k)=toc(Tm);
end
0 件のコメント
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