Interleaved repmat (row duplication)

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Albert
Albert 2021 年 11 月 5 日
コメント済み: Albert 2021 年 11 月 5 日
I would like to do a specific repmat such that if I have:
a=[1 0 0;0 0 1;1 1 1]
a = 3×3
1 0 0 0 0 1 1 1 1
I would like to duplicate each row by a value N, so that in the case N = 2 each row will be duplicated twice:
b=[1 0 0;1 0 0;0 0 1;0 0 1;1 1 1;1 1 1]
b = 6×3
1 0 0 1 0 0 0 0 1 0 0 1 1 1 1 1 1 1
Is there an easy way of doing this interleaved repmat? Thanks

採用された回答

Stephen23
Stephen23 2021 年 11 月 5 日
The simple and efficient approach is to use REPELEM:
a = [1,0,0;0,0,1;1,1,1]
a = 3×3
1 0 0 0 0 1 1 1 1
b = repelem(a,2,1)
b = 6×3
1 0 0 1 0 0 0 0 1 0 0 1 1 1 1 1 1 1
  1 件のコメント
Albert
Albert 2021 年 11 月 5 日
Very elegant solution indeed! I found another option which is:
a = [1,0,0;0,0,1;1,1,1];
reshape(repmat(a',2,1),size(a,2),size(a,1)*2)'
ans = 6×3
1 0 0 1 0 0 0 0 1 0 0 1 1 1 1 1 1 1
But yours is much better. thanks!

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その他の回答 (1 件)

Sudharsana Iyengar
Sudharsana Iyengar 2021 年 11 月 5 日
Try this
A=[1,0,0; 0 0 1; 1 1 1;];
k=1;
for i =1:3
T(k:k+1,:)=repmat(A(i,:),2,1);
k=k+2;
end
T
T = 6×3
1 0 0 1 0 0 0 0 1 0 0 1 1 1 1 1 1 1

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