Creating a matrix of sinusoids with frequency increasing over columns and time increasing over rows

I need to create a matrix/array of sinusoids with time vector increasing along rows and frequency vector increasing along columns.

t = a:int:b

f = c:int:d

y(t, f) = sin(2*pi*f*t)

The desired result is as follows (column and row headings are added for clarity of the question here):

Y{} =

          f0               f1              f2       ...        fn
   --                                                                  --
t0 |sin(2*pi*f0*t0) sin(2*pi*f1*t0) sin(2*pi*f2*t0) ...  sin(2*pi*fn*t0)|
t1 |sin(2*pi*f0*t1) sin(2*pi*f1*t1) sin(2*pi*f2*t1) ...  sin(2*pi*fn*t1)|
t2 |sin(2*pi*f0*t2) sin(2*pi*f1*t2) sin(2*pi*f2*t2) ...  sin(2*pi*fn*t2)|
...|     ...             ...             ...        ...        ...      |
tn |sin(2*pi*f0*tn) sin(2*pi*f1*tn) sin(2*pi*f2*tn) ...  sin(2*pi*fn*tn)|
   --                                                                  --

Help is appreciated, thanks

Answer 1

[Mohammad Abouali]

minT=0;
maxT=1;
dT=0.01;
minF=1;
maxF=4;
dF=1;
[Time,frequency]=ndgrid( minT:dT:maxT , minF:dF:maxF );

y=sin(2*pi*frequency.*Time);

plot(Time,y);axis tight

[Nate]

Great thanks. also works

[Matt J]

Rick's version is more efficient, however. The use of ndgrid consumes more time and memory than the simple outer product t*Fc.

Answer 2

[Rick Rosson]

Fs = 48000;
dt = 1/Fs;
t = (0:dt:0.25-dt)';

Fc = 60*(1:2:15);

y = sin(2*pi*t*Fc);

[Nate]

Thanks, yes this works as well.