Easy convolution of multiple vectors

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Daniel
Daniel 2014 年 9 月 23 日
コメント済み: Matt J 2014 年 9 月 23 日
For the convolution of three vectors I'm doing:
A = [1 2];
B = [3 4];
C = [5 6];
res_aux = conv(A,B);
res = conv(res_aux,C);
Is there an easier way? Something like: res = multiconv({A,B,C})
An alternative would be using cellfun but it's slower.

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Matt J
Matt J 2014 年 9 月 23 日
編集済み: Matt J 2014 年 9 月 23 日
Here's an fft-based approach
data=[1 2;3 4;5 6].';
n=(size(data,1)-1)*size(data,2)+1;
result = ifft(prod(fft(data,n),2),'symmetric')
  2 件のコメント
Daniel
Daniel 2014 年 9 月 23 日
Thank you Matt!
I had read about using fft to solve this but I couldn't understand how. Your comment was of great help.
I'm marking this as answered. Once again, thank you!
Matt J
Matt J 2014 年 9 月 23 日
OK. I'm not sure it's faster/more efficient than a plain for-loop, though. It involves complex-valued arithmetic and probably about 4 times more memory consumption.

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