find missing elements in a matrix

Hi, I have a matrix represents code numbers.

    A=[1 2 3 6 7 45 46 47 53 78 80];
    B=[55.23                ,74.22]; % B is if same length of A, and contains element by element corresponding data

Say the numbers should be in the range 1:80.

How can I find the numbers which are missing in A.

eg in above case, the expected answer is missing=[4 5 8 9    ... 79]

Then to print a text file

experiment 1 results 55.23
experiment 2 results 442.23 
experiment 4 data missing
.
.
experiment 79 data missing
experiment 80 results 442.2

[Stephen23]

Your edit added "Then print to a text file". This is:

• A separate topic.
• Easy to solve yourself using any search engine.

Other users here are not paid to write your code for you, but will happily help if there is something that needs explaining or clarification.

[Rashmil Dahanayake]

^ non technical comment. Scroll down to read relevant answers.

Answer 1

[Stephen23]

Try setxor :

setxor(A,1:80)

[Stephen23]

See also Fabio Freschi's answer using setdiff .

[Rashmil Dahanayake]

see my updated answer incorporating Fabios

Answer 2

[Fabio Freschi]

Try this

 A=[1 2 3 6 7 45 46 47 53 78 80];
 all = 1:80;
 missing = setdiff(all,A);

Fabio

[Rashmil Dahanayake]

this method also works

Answer 3

[Rashmil Dahanayake]

Full Answer for my question asked previously. In case if someone might find it usefull

A=1:3:20;  % in complete data
B=1:20;    % Full index
missing = setdiff(B,A); % check for missing elements
A=strread(num2str(A),'%s')'; 
for ms=1:length(missing)
A=horzcat(A(1:(missing(ms)-1)),'misplaced results',A(missing(ms):end));
end
%A  % verify answer