hello,
i have to implement a MATLAB function findmanyzeros of the form function p = findmanyzeros(f, a, b, n, which finds zeros in the interval [a, b] using the following strategy:
1. Compute n+1 equidistant points xk , k=0,...,n, between a and b
2. For k = 1,...,n, if f(xk) and f(xk1) have different signs, compute a zero using findzero
3. The output vector p should contain all the computed zeros
my code is as follows:
function p = findmanyzeros(f, a, b, n, tol)
n=n+1;
for k = 1:n
if f(xk)*f(xk-1)<0
findzero(f);
end
end
p
my code is wrong and i could really appriciate some help, thanks.

 採用された回答

Jan
Jan 2021 年 9 月 29 日
編集済み: Jan 2021 年 9 月 30 日

0 投票

This homework question contains useful instructions already:
"Compute n+1 equidistant points xk , k=0,...,n, between a and b"
You've omitted this step. Use the command linspace() to solve it and assign the output to the variable x.
Then you can use f(x(k)) and f(x(k+1)).
I guess, that calling findzero needs the variable tol. Assign the output of this function to p(k).

4 件のコメント

Walter Roberson
Walter Roberson 2021 年 9 月 29 日
However, the output is only to be the list of zeros, so if you assign to p(k) you need to collapse the list later to remove the places no zero was found.
Lavorizia Vaughn
Lavorizia Vaughn 2021 年 9 月 30 日
the new code i have is as follows:
function p = findz(f,a,b,n,tol)
x = linspace(a,b,n+1);
p = [];
for k = 2:length(x)
if f(x(k)) * f(x(k-1)) > 0
continue
else
z = findzero(f,x(k-1),x(k),tol);
p = [p,z];
end
end
disp(p)
end
i am getting the error Unrecognized function or variable 'findzero'.
Stephen23
Stephen23 2021 年 9 月 30 日
"Unrecognized function or variable 'findzero'."
FINDZERO is not a MATLAB function. Did you mean FZERO?:
Lavorizia Vaughn
Lavorizia Vaughn 2021 年 9 月 30 日
Yes I had the file findzero named wrong. Thanks for the help.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

ヘルプ センター および File ExchangeEigenvalues についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by