Dimensions of arrays being concatenated are not consistent.

Question

Robert Demyanovich 2021 年 9 月 27 日

回答済み: Stephen23 2021 年 9 月 27 日

I have no idea why I am getting an error in the following code:

FluorDataInd = round(i/TimeFactor)+1

x=[ConcValues{1,1} ConcValues{1,2} ConcValues{1,3} ConcValues{1,4} ConcValues{1,5}]'; y=[FluorData{FluorDataInd,3}

FluorData{FluorDataInd,4} FluorData{FluorDataInd,5} FluorData{FluorDataInd,6} FluorData{FluorDataInd,7}]';

[cf G]=L4P(x,y)

The error I am getting is:

457 x=[ConcValues{1,1} ConcValues{1,2} ConcValues{1,3} ConcValues{1,4} ConcValues{1,5}]'; y=[FluorData{FluorDataInd,3}

Error using vertcat

Dimensions of arrays being concatenated are not consistent.

So for the x = statement, all of the variables need to be values. For example, the following does not produce any errors"

x=[1E-07 1E-02 5E-13 1E-10 1E-04]'; y=[102.992 130.6 48.1917 51.083202 127.988]';

[cf G]=L4P(x,y)

FluorDataInd provides the row number for the table FluorData.  So, I don't see what the problem is.

Answer 1

Stephen23 2021 年 9 月 27 日

The problem is the line-break without any ellipses. But your code can be simplified anyway, removing that problem:

x = [ConcValues{1,1:5}].';
y = [FluorData{FluorDataInd,3:7}].';