Dimensions of arrays being concatenated are not consistent.

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Robert Demyanovich
Robert Demyanovich 2021 年 9 月 27 日
回答済み: Stephen23 2021 年 9 月 27 日
I have no idea why I am getting an error in the following code:
FluorDataInd = round(i/TimeFactor)+1
x=[ConcValues{1,1} ConcValues{1,2} ConcValues{1,3} ConcValues{1,4} ConcValues{1,5}]'; y=[FluorData{FluorDataInd,3}
FluorData{FluorDataInd,4} FluorData{FluorDataInd,5} FluorData{FluorDataInd,6} FluorData{FluorDataInd,7}]';
[cf G]=L4P(x,y)
The error I am getting is:
457 x=[ConcValues{1,1} ConcValues{1,2} ConcValues{1,3} ConcValues{1,4} ConcValues{1,5}]'; y=[FluorData{FluorDataInd,3}
Error using vertcat
Dimensions of arrays being concatenated are not consistent.
So for the x = statement, all of the variables need to be values. For example, the following does not produce any errors"
x=[1E-07 1E-02 5E-13 1E-10 1E-04]'; y=[102.992 130.6 48.1917 51.083202 127.988]';
[cf G]=L4P(x,y)
FluorDataInd provides the row number for the table FluorData. So, I don't see what the problem is.

採用された回答

Stephen23
Stephen23 2021 年 9 月 27 日
The problem is the line-break without any ellipses. But your code can be simplified anyway, removing that problem:
x = [ConcValues{1,1:5}].';
y = [FluorData{FluorDataInd,3:7}].';
See also:

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