Normalize unit vector to single didgit integers

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Jacob Weiss
Jacob Weiss 2021 年 9 月 15 日
編集済み: Stephen 2021 年 9 月 16 日
I am trying to normalize a vector to integers. For example, I would like [ .4 .-4 .8] to be [ 1 -1 2]. However, if it is not a perfect for example, [.123 .123 .5] would be [123 123 500] but I would like it to be rounded to a single didgit integer. I.E instead of [123 123 500] it would be [1 1 5].
Ive seen v=x/norm(x) but this does not work even for obvious cases.

回答 (2 件)

the cyclist
the cyclist 2021 年 9 月 15 日
Does the following do what you want?
f = @(t) round(t/abs(min(t)));
f([ 0.4 -0.4 0.8])
ans = 1×3
1 -1 2
f([ 0.123 0.123 .5])
ans = 1×3
1 1 4
It gives a different result for your second example, but I think it is a better normalization because it is closer to the original ratio.

Stephen
Stephen 2021 年 9 月 16 日
編集済み: Stephen 2021 年 9 月 16 日
fun = @(V) round(V./10.^floor(log10(abs(V))));
fun([0.4,-0.4,0.8])
ans = 1×3
4 -4 8
fun([0.123,0.123,0.5])
ans = 1×3
1 1 5
Note that this scales each element independently, to give the result you asked for. The ratio of values is better represented by the cyclist's answer.

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