Counting number of words and their characters

oo

[Stephen23]

Original question by Joe Ainsworth on 3rd Septempber 2021 retrieved from Google Cache:

https://web.archive.org/web/20211024181845/https://webcache.googleusercontent.com/search?q=cache%3A_nMWuDzVc9YJ%3Ahttps%3A%2F%2Fwww.mathworks.com%2Fmatlabcentral%2Fanswers%2F1445949-counting-number-of-words-and-their-characters

Counting number of words and their characters

Hi all,

currenlty wirting a script which reads a text file, splits the lines into the individual words and stores the word lengths in an array.

i beleive this may be achieveable with a bag of words but it may not be neccessary or the simpliest way to do so.

print the total number of words, the number of characters within the words but dosesnt count spaces but does incude punctuation and the lengths of the individual words.

Needs to be outputted like so.

This file has zz words with bb characters

* Word x has yy characters

any insight is much appreciated

Answer 1

[Ive J]

Maybe this help

txt = ["Why MATLAB doesn't offer much for data science?"; "Python and R beat MATLAB in ML"];
voc = tokenizedDocument(txt).Vocabulary;
len = arrayfun(@(x)numel(x{:}), voc);

% print document stat
wordn = voc + " has " + len + " characters";

fprintf('file txt has %d words with %d characters:\n', numel(voc), sum(len))

file txt has 15 words with 58 characters:

fprintf('\t%s\n', wordn.')

	Why has 3 characters
	MATLAB has 6 characters
	doesn't has 7 characters
	offer has 5 characters
	much has 4 characters
	for has 3 characters
	data has 4 characters
	science has 7 characters
	? has 1 characters
	Python has 6 characters
	and has 3 characters
	R has 1 characters
	beat has 4 characters
	in has 2 characters
	ML has 2 characters

[Joe Ainsworth]

This doesn't use opening a txt file, youve just typed in the data you want to read?

[Ive J]

You have lots of options for reading txt files:

doc extractFileText
doc readlines
doc fileread

[Joe Ainsworth]

thanks @Ive J, im trying to use fileread as per below, but its then giving me an error on line 4;

Error in Word_lengths (line 4)

voc = tokenizedDocument(txt).Vocabulary;

this is the code below

inputfile = fileread('SampleText.txt');

voc = tokenizedDocument(inputfile).Vocabulary;
len = arrayfun(@(x)numel(x{:}), voc);
% print document stat
wordn = voc + " has " + len + " characters";
fprintf('file txt has %d words with %d characters:\n', numel(voc), sum(len))

fprintf('\t%s\n', wordn.')

[Ive J]

Can you upload SampleText.txt?

[Joe Ainsworth]

sure

[Ive J]

I don't get any error.

file txt has 6 words with 18 characters:
	I has 1 characters
	love has 4 characters
	golf has 4 characters
	. has 1 characters
	hit has 3 characters
	bombs has 5 characters

Can you specify what version of MATLAB do you use and what's the error msg?

[Joe Ainsworth]

using matlab2021a, error message

tokenizedDocument' requires Text Analytics Toolbox.

Error in Word_lengths (line 5)

voc = tokenizedDocument(inputfile).Vocabulary;

[Ive J]

Well, seems you haven't Text Analytics Toolbox.

contains(struct2array(ver), 'Text Analytics Toolbox') % true is installed

ans = logical
   1

In that case you can use a mixture of regexp and split to get the words. The challenge lies in punctuations. Consider my first example again:

txt = ["Why MATLAB (R2021) doesn't offer much for data science?!"; "Python and R, both beat MATLAB in ML."];
txt = join(txt, newline);
% replace the above lines with the following when reading from text files
% txt = string(fileread('myfile.txt'));

voc = unique(split(txt)); % we keep unique words, so each word is counted only once through the document.

% find punctuations
patt = regexpPattern('[^\w\s]');
punc = extract(txt, patt);
punc(punc == "'") = []; % keep apostrophes intact
voc = replace(voc, punc, ''); % remove punctuations from voc
voc = [voc; punc]; % merge all together
len = arrayfun(@(x)numel(x{:}), voc);
% print document stat
wordn = voc + " has " + len + " characters";
fprintf('file txt has %d words with %d characters:\n', numel(voc), sum(len))

file txt has 22 words with 72 characters:

fprintf('\t%s\n', wordn.')

	R2021 has 5 characters
	MATLAB has 6 characters
	ML has 2 characters
	Python has 6 characters
	R has 1 characters
	Why has 3 characters
	and has 3 characters
	beat has 4 characters
	both has 4 characters
	data has 4 characters
	doesn't has 7 characters
	for has 3 characters
	in has 2 characters
	much has 4 characters
	offer has 5 characters
	science has 7 characters
	( has 1 characters
	) has 1 characters
	? has 1 characters
	! has 1 characters
	, has 1 characters
	. has 1 characters