フィルターのクリア

Code of Iterative method's test

1 回表示 (過去 30 日間)
Fatima Al Marzoqi
Fatima Al Marzoqi 2014 年 7 月 12 日
コメント済み: Roger Stafford 2014 年 7 月 12 日
I wrote a code to solve a linear system using Successive Relaxation Iterative method
but I don't know how to add the test and write its code
can anyone help me
  4 件のコメント
Jan
Jan 2014 年 7 月 12 日
編集済み: Jan 2014 年 7 月 12 日
Which "test" do you mean? Please explain all required details. We cannot guess them.
Matt J
Matt J 2014 年 7 月 12 日
When you call the function with some sample input, do you get the output you expect? If so, what more is there to do?

サインインしてコメントする。

回答 (2 件)

Roger Stafford
Roger Stafford 2014 年 7 月 12 日
It looks as though you might be testing to see if the square matrix, R, fails to be "diagonally dominant". If so, here is a method:
Ra = abs(R);
if any(sum(Ra,2)>2*diag(Ra))
display ('Test Failed')
end
  4 件のコメント
Fatima Al Marzoqi
Fatima Al Marzoqi 2014 年 7 月 12 日
yes that what I want .. but it doesn't work with my code !
check please , I attach my code
Roger Stafford
Roger Stafford 2014 年 7 月 12 日
I don't see anything like my code in your 'proj.m' code. Where are you doing a test remotely resembling "any(sum(Ra,2)>2*diag(Ra))"? Nowhere do you have an 'any' command nor do you ever multiply anything by 2. You don't even have a 'sum' command!
If you want effective help here it would be best to explain your problem much more clearly than you have so far done. What precisely is your test supposed to accomplish and in what way is it related to the matrix you called 'R'?

サインインしてコメントする。


Fatima Al Marzoqi
Fatima Al Marzoqi 2014 年 7 月 12 日
it is a loop that we apply for each row the on diagonal element must be greater than the rest elements
%Test
for i=1:4
for j=4:-1:1
if j~=i
S=sum(abs(R(i,j)));
end
end
if abs(R(i,i))<S
display ('Test Failed');
fprintf(fid,'Test Failed')
break
end
end

カテゴリ

Help Center および File ExchangeHypothesis Tests についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by