Multi Subplot for loop

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Eric
Eric 2014 年 6 月 12 日
コメント済み: Geoff Hayes 2018 年 4 月 23 日
Hi, I want to work with two subplots to record data from each iteration of a loop but am not sure how to do this. Code is something like this as of now:
for i = 2:2:12
[C,L,p,S] = func1(n,i)
subplot1 = subplot(2,3,i/2)
semilogx(p,C,p,L)
subplot2 = subplot(2,3,i/2)
semilogx(p,S)
end
Please let me know if there is an easy way to switch between the two in each loop, as right now C,L, and S are shown on the same graphs but I want C and L together with S on a separate subplot. The reason I want to do this is because the range of C and L is 0 to 1, and the range of S is 0 to 40. Please let me know if you need anything further clarified.
  2 件のコメント
Ramesh Bala
Ramesh Bala 2018 年 4 月 22 日
編集済み: Geoff Hayes 2018 年 4 月 23 日

I have a question? Unable to plot the matrix values separately The subplot should plot 6,11,16,21,26 separately But its plotting only 26...any idea

for i=6:5:26
%     figure(i)
    for j=1:1:5
        subplot(5,1,j);
        plot(s.data(1,i).wektor_czasu(1,1:10761),s.data(1,i).pomiar(4,1:10761));
    end
end
Geoff Hayes
Geoff Hayes 2018 年 4 月 23 日

Kaleesh - you need to use hold to retain the current plot when adding a new one. Probably something like

 for i=6:5:26
    hold(subplot(5,1,j), 'on');
    for j=1:1:5
        subplot(5,1,j);
        plot(s.data(1,i).wektor_czasu(1,1:10761),s.data(1,i).pomiar(4,1:10761));
    end
 end

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回答 (3 件)

Geoff Hayes
Geoff Hayes 2014 年 6 月 12 日
The above code keeps referring to the same subplot on each iteration since it is using i/2 for each i in either subplot1 = subplot(2,3,i/2) or subplot2 = subplot(2,3,i/2). A different grid position is needed for each subplot.
There are six iterations of the for loop, so presumably there will be 6 pairs of subplots (so 12 subplots in total). Is this correct? The above code indicates that there will be six iterations (due to the 2:2*12) but then a 2x3 is defined using subplot (for only 6 subplots) hence the confusion. If we assume the the six pairs then we can do the following
for i = 2:2:12
[C,L,p,S] = func1(n,i);
subplot1 = subplot(6,2,i-1);
semilogx(p,C,p,L);
subplot2 = subplot(6,2,i);
semilogx(p,S);
end
From http://www.mathworks.com/help/matlab/ref/subplot.html, MATLAB numbers its grids by row, such that the first grid is the first column of the first row, the second grid is the second column of the first row, and so on. So the two grids in the first row are accessed by 1 and 2, the two in the second row are accessed by 3 and 4, etc.
Since i is a multiple of 2, then on the first iteration we want to update subplots/grids 1 and 2 (so i-1 and i for i==2), on the second iteration we want to update subplots/grids 3 and 4 (again, i-1 and i for i==4), etc. That is why the above uses subplot(6,2,i-1) and subplot(6,2,i).
Try the above and see what happens!

dpb
dpb 2014 年 6 月 12 日
How about plotyy instead?
But, since suplots are numbered from L to R by row, they're
1 2 3
4 5 6
in your window.
for i=2:2:12
[C,L,p,S] = func1(n,i)
subplot1 = subplot(2,3,i/2);
semilogx(p,C,p,L)
subplot2 = subplot(2,3,i/2+3);
semilogx(p,S)
end

Eric
Eric 2014 年 6 月 13 日
hey guys, thanks for all the helpful suggestions. I ended up figuring it out exactly as I wanted to; here's how I personally did it:
for i = 2:4
figure(1)
subplot(1,3,i-1)
semilogx(....
....
figure(2)
subplot(1,3,i-1)
semilogx(different plot data...)
...
end
  2 件のコメント
José-Luis
José-Luis 2014 年 6 月 13 日
Please accept an answer if it solved your problem
Image Analyst
Image Analyst 2014 年 6 月 14 日
Eric, you can also vote for them as well to give the people reputation points.

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