How do I convert a time domain signal to frequency domain?
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I am having some problems converting a time domain signal into frequency domain--I don't have constant sampling time.
In time domain, is this the way to plot the graph?
value = [42007935 111212895 184546560 238219725 238219725 184546560 111212895 42007935]; time = [0, ,5,1.25,2, 2,5,5, 4, 4.5, 6, 7, 8 ];
plot (time, value);
X and/or Y arguments ignored.
Could anyone help me plot a signal that does not have constant time?
2 件のコメント
Star Strider
2014 年 5 月 12 日
If you want to plot them, your time and value arrays have to have the same number of elements. They don’t.
dpb
2014 年 5 月 12 日
編集済み: dpb
2014 年 5 月 12 日
Look for NUFFT (non-uniform FFT) literature -- there's quite a lot.
You surely have the sample times or at least delta-t's, don't you? W/o that you have nothing.
Don't believe TMW has an implementation packaged as yet, anyway.
ADDENDUM:
You might check the File Exchange for submissions and of course there's always a search including Matlab in the search.
回答 (2 件)
Vilnis Liepins
2014 年 5 月 13 日
Hello,
To convert nonuniform time domain data to frequency domain you can use Extended DFT (program NEDFT.m) available on fileexchange http://www.mathworks.com/matlabcentral/fileexchange/11020-extended-dft
NEDFT call line:
F=nedft(value,time,fn);
where frequencies [fn] could be generated as
fn=[-ceil((N-1)/2):floor((N-1)/2)]/N/T;
As I see from your example [time] data the mean sampling frequency T=1. The length of DFT N usually is set equal to or greater than the length(value) that, as Star Strider commented, should have the same dimensions as [time] array.
After that you also be able to get back constant time version of your data [value1] by applying IFFT to the result of NEDFT, call line:
value1=real(ifft(fftshift(F)));
Vilnis Liepins
2014 年 5 月 19 日
編集済み: Vilnis Liepins
2014 年 5 月 19 日
Actually they are specified in your post:
>> value = [42007935 111212895 184546560 238219725 238219725 184546560 111212895 42007935];
>> time = [0, ,5,1.25,2, 2,5,5, 4, 4.5, 6, 7, 8 ];
Note that you need to correct the 'time' vector: time(1)<time(2)<time(3)<... and length(value) must be equal to length(time):
- the signal value(1)=42007935 is taken at time(1),
- the signal value(2)=111212895 is taken at time(2), and so on.
8 件のコメント
dpb
2014 年 5 月 28 日
It's about four or five comments past...you only need to use the
"Show N older comments"
button to see the previous that have been collapsed by the viewer by default.
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