Access a single element of an anonymous function that returns an array
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I have an anonymous function that returns an array. I'd like to be able to create a new anonymous function that consists of a single element of this array WITHOUT using matlabfunction (which is infuriatingly restrictive in several respects).
For example, consider the following code (it's a ridiculously simple example, for expository purposes, obviously there are easy ways of dealing with this example, but my real problem is more complex)
y = sym('y',[1,4])
f = @(y)[y(1);y(2);y(3);y(4)]
f(y)
which returns
ans =
y1
y2
y3
y4
I'd now like to define a new anonymous function which extracts, say, the third element of this array. Obviously,
g = @(y) f(y)(3)
won't work. Is there some way to accomplish this? Again, solns involving matlabfunction are not satisfactory.
Any suggestions would be most appreciated!
Leo
0 件のコメント
採用された回答
Walter Roberson
2014 年 4 月 27 日
indexat = @(expr, index) expr(index);
g = @(y) indexat(f(y), 3);
2 件のコメント
Stephen23
2020 年 4 月 7 日
"could you please explain what you mean by "expr" and "index"? "
They are the input arguments of an anonymous function:
その他の回答 (1 件)
Lauren Barr
2020 年 4 月 20 日
This is really helpful, thank you! I was wondering if there is a way to extend it, so that I can index one particular value in a 2D matrix, instead of indexing into a vector?
For example, this doesn't seem to work:
indexat = @(expr, index) expr(index);
g = @(y) indexat(f(y), (1,3));
But maybe I am missing something obvious.
Thank you!
Lauren
2 件のコメント
Lauren Barr
2020 年 4 月 20 日
I think I found the answer here!
Stephen23
2020 年 4 月 20 日
You can create a general solution for any number of dimensions:
indexat = @(expr, varargin) expr(varargin{:});
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