How to interpret matrix indexation? Help to translate specific case please.
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Hi;
I am new using MATLAB, I regularly make programs in C++ and I am trying to translate the following piece of code into C++. I understand how repmat works and some of the indexations of matrices but I have been searching and I really have not found nor understood how does the last line works. I understand I am assigning "something" to F1, what I specifically do not understand is the part between brackets []. I reckon the colon is to "copy" the entire column and the number 1 in the ends refers that the F1 is the one I am getting the info. I my assumptions are correct please let me know.
I appreciate your time and your help to explain me. Thank you!
MATLAB code
nx=3; ny=3;
F=repmat(0.11,[nx ny 2]);
F(:,:,1)=F([nx 1:nx-1],:,1)
1 件のコメント
dpb
2014 年 3 月 17 日
Why don't you just look at it in the command window? Using some data other than a constant so you can see specifically who came from where would make it easier.
[nx 1:nx=1]
is a vector--in you specific case it's easily enough seen by simply plugging in values to be
[3 1:3-2] --> [3 1:2] --> [3 1 2]
採用された回答
Marta Salas
2014 年 3 月 17 日
編集済み: Marta Salas
2014 年 3 月 17 日
You create a a 3dimesional matrix with the repmat: 3x3x2
The last line of code takes the matrix assigned on 3rd dimesion= 1 and reorders the rows. The code in brackets is the new order ([3 1 2] in your example)
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