Melda Harlova
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質問
Problem solving DE neural network
Hi, I need a help with this solution expecially with the last line mesh(x1,x2,y). Error: Unrecognized function or variable 'x1...
5年弱 前 | 0 件の回答 | 0
0
回答質問
Differential equation and problem with minmax
Hi everyone, I have an error in that line: net=newff(minmax(p),[3,1],{'tansig','purelin'},'trainlm') And this error 'minmax'...
5年弱 前 | 1 件の回答 | 0
1
回答質問
Problem with differential equation net
Hello, I have a problem with using net in following code. Thank you in advance. clear all x=-1:0.1:3; z=x; net=newff(minm...
5年弱 前 | 0 件の回答 | 0
0
回答質問
Problem with threee differential equations
Can someone help me with these three equatons. They have to solve with matlab code. Here are : 1. y'' - y = 0 y(0)=0 y(1)=...
5年弱 前 | 0 件の回答 | 0
0
回答質問
Problem with statistics and line of regression
Hello, I dont know if the place for my question is here, but i will be thankful if someone help me. I have a problem with deci...
5年以上 前 | 0 件の回答 | 0
0
回答質問
Line of regression statistics problem
Hello, I dont know if the place for my question is here, but i will be thankful if someone help me. I have a problem with deci...
5年以上 前 | 0 件の回答 | 0
0
回答質問
Method of finite differences
Hello, i have to solve this with a method of finite differences x'' = -2x'(t) – 2x(t) + e^(-t) + sin(2t) t ϵ [0,4]; x(0) = 0,...
5年以上 前 | 0 件の回答 | 0
0
回答質問
Problem with the shooting method
Helloo, Can someone help me with that code in matlab: function main y0=0; y0=fsolve(@fun1,y0); x0=[0.6,y0]; [t,x]=ode45(...
5年以上 前 | 0 件の回答 | 0
0
回答質問
How to solve matrix exponent equation
Hello, I will be thankful if someone helps me. Here is my task: Reduce to a system and solve a matrix exponent equation under ...
5年以上 前 | 0 件の回答 | 0
0
回答質問
Runge Kutta 4th order
Hello, Here is the task that i have to solve: y1' = y2 y2'=f(x,y1,y2) with y1(0)=0 and y2(0)=y20 where f(x,y1,y2) = -axy2-...
5年以上 前 | 13 件の回答 | 0
13
回答質問
Runge Kutta for system of differential equations
Hello, I have to solve the following system with method of Runge Kutta: y1' = y2 y2'=f(x,y1,y2) with y1(0)=0 and y2(0)=y20 ...
5年以上 前 | 0 件の回答 | 0