ha9981


2012 年からアクティブ

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Designing DTMF Generator on SImulink
I have looked at the example called DSPDTMF. I do not seem to understand it. Could someone guide me on how to design a DTMF gene...

11年以上 前 | 0 件の回答 | 0

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Matlab 2012a subs() BUG?
I have function that is a sum of multiple sinusoidal functions. It is x(t). I try to first do time shift, no problem: sy...

12年弱 前 | 0 件の回答 | 0

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How do I plot a fourier transform?
syms t w x1 = sin(2*pi*20*t)*cos(2*pi*2000*t); x2 = sin(2*pi*40*t)*cos(2*pi*4000*t); x = x1+x2; X= fourier(x,t...

約12年 前 | 1 件の回答 | 0

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Signals and Systems: Designing a filter using invfreqs?
Given a time-domain sinusoidal function like this: x(t) = sin(at)cos(bt) + sin(ct)cost(dt) How do I filter out one term usin...

約12年 前 | 0 件の回答 | 0

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Numeric Integration for Fourier Transform
I need to do a fourier transform of a function that I have only a vector for. So given a vector y and time t. t= linspace(...

約12年 前 | 0 件の回答 | 0

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Convolution of Fourier Series Coefficients
So I have generated the fourier series coefficients for x(t) and y(t). I know that if z(t) = x(t)y(t) then in the frequency doma...

12年以上 前 | 1 件の回答 | 0

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Am I finding the Step and Impulse Response Correctly?
Given the function: dy(t)/dt + 3y(t) = x(t) step([1],[1,3],t); impulse([1],[1,3],x,t);

12年以上 前 | 1 件の回答 | 0

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What is the method to get step response of differential order system?
Should I do laplace first and then do a step response of the laplace. I have never used Matlab to such degree and am very con...

12年以上 前 | 1 件の回答 | 0

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Calculating Fourier Series Coefficients Using Custom Matlab Function
My attempt at creating such a function where it must have the three inputs x, w0, and N: function[ak] = cal_fs(x, w0, N) ...

12年以上 前 | 2 件の回答 | 0

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How to transform function in MatLab? Shift, Scale etc.
http://www.mathworks.com/help/symbolic/subs.html I think I found it. Appears to work. x3 = subs(x1, t, t-2) Is this a c...

12年以上 前 | 1

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How to transform function in MatLab? Shift, Scale etc.
If I have a function as follows: syms x1; syms t; x1 = exp(t)* Heaviside(2*t); How do I do define x2 = x1(t-2) so ...

12年以上 前 | 3 件の回答 | 0

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