photo

Aramis


Last seen: 3ヶ月 前 |  2024 年からアクティブ

Followers: 0   Following: 0

統計

  • First Answer

バッジを表示

Feeds

表示方法

回答済み
how to find the element which is greater than or equal to its row and smaller or equal to its column in a matrix
The best solution function s = saddle(M) % Create logical vector that are true for each saddle condition separately m...

5ヶ月 前 | 0

回答済み
Sparse Matrix, struct, structure, Using cell arrays
function matrix = sparse2matrix(cellvec) matrix = ones(cellvec{1}) * cellvec{2}; for x=3:length(cellvec) matr...

7ヶ月 前 | 0

回答済み
next prime number using While loops
THE BEST ANSWER function k = next_prime(n) k=n; while isprime(k)==false || k==n k = k+1; end end ...

10ヶ月 前 | 0

回答済み
Write a function called valid_date that takes three positive integer scalar inputs year, month, day. If these three represent a valid date, return a logical true, otherwise false. The name of the output argument is valid.
The best answer function valid = valid_date(year,month,day) if not(isscalar(year))|| not(isscalar(month)) || not(isscalar(...

10ヶ月 前 | 1

回答済み
Write a function called eligible that helps the admission officer of the Graduate School decide whether the applicant is eligible for admission based on GRE scores. The function takes two positive scalars called v and q as in
This is the BEST FCKN ANSWER function admit = eligible(v, q) admit = mean([v q]) >= 92 && min([v q]) > 88; end

10ヶ月 前 | 1

回答済み
Write a function called minimax that takes M, a matrix input argument and returns mmr, a row vector containing the absolute values of the difference between the maximum and minimum valued elements in each row. As a second output argument called mmm,
function [x, y] = minimax(M) x = (max(M,[],2) - min(M,[],2))'; y = max(M,[], "all")- min(M,[], "all"); end

10ヶ月 前 | 0