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Naveen Gehlot


Last seen: 2年弱 前 |  2020 以来アクティブ

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Solving 2nd part of minimax question
function [mmr, mmm]= minimax (A) mmr = [max(A,[],2)- min(A,[],2)]'; mmm = max(A,[],'all')-min(A,[],'all'); OUTPUT mmr =...

2年弱 前 | 0