Problem 2336. Calendar Matrix

Created by Ned Gulley

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<p>Return a calendar matrix for the given values of month and year. Assume that Sunday is the first day of the week. The resulting calendar month will have seven columns and only as many rows (weeks) as needed to display all days of the month. Thus it might have either 4, 5, or 6 rows. Days preceding the first of the month or following the last of the month are given by zeros.</p><p>Examples</p><pre> &gt;&gt; mo = 1
 &gt;&gt; yr = 2014
 &gt;&gt; momat = makeCalendar(mo,yr)</pre><pre>     0     0     0     1     2     3     4
     5     6     7     8     9    10    11
    12    13    14    15    16    17    18
    19    20    21    22    23    24    25
    26    27    28    29    30    31     0</pre><pre> &gt;&gt; mo = 2
 &gt;&gt; yr = 2015
 &gt;&gt; momat = makeCalendar(mo,yr)</pre><pre>     1     2     3     4     5     6     7
     8     9    10    11    12    13    14
    15    16    17    18    19    20    21
    22    23    24    25    26    27    28</pre><pre> &gt;&gt; mo = 10
 &gt;&gt; yr = 2010
 &gt;&gt; momat = makeCalendar(mo,yr)</pre><pre>     0     0     0     0     0     1     2
     3     4     5     6     7     8     9
    10    11    12    13    14    15    16
    17    18    19    20    21    22    23
    24    25    26    27    28    29    30
    31     0     0     0     0     0     0</pre>

Return a calendar matrix for the given values of month and year. Assume that Sunday is the first day of the week. The resulting calendar month will have seven columns and only as many rows (weeks) as needed to display all days of the month. Thus it might have either 4, 5, or 6 rows. Days preceding the first of the month or following the last of the month are given by zeros.

Examples

>> mo = 1
 >> yr = 2014
 >> momat = makeCalendar(mo,yr)

0     0     0     1     2     3     4
     5     6     7     8     9    10    11
    12    13    14    15    16    17    18
    19    20    21    22    23    24    25
    26    27    28    29    30    31     0

>> mo = 2
 >> yr = 2015
 >> momat = makeCalendar(mo,yr)

1     2     3     4     5     6     7
     8     9    10    11    12    13    14
    15    16    17    18    19    20    21
    22    23    24    25    26    27    28

>> mo = 10
 >> yr = 2010
 >> momat = makeCalendar(mo,yr)

0     0     0     0     0     1     2
     3     4     5     6     7     8     9
    10    11    12    13    14    15    16
    17    18    19    20    21    22    23
    24    25    26    27    28    29    30
    31     0     0     0     0     0     0

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Last Solution submitted on Sep 13, 2021

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1 Comment

Ned Gulley on 23 May 2014

I appreciate how you keep at it even after you found the calendar function! I confess I never knew about calendar.m until today!

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