Problem 2019. Dimensions of a rectangle

Created by Tanya Morton

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3939 Solutions
1985 Solvers

Last Solution submitted on Sep 21, 2020

Last 200 Solutions

Problem Comments

7 Comments

7 Comments

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Dominik on 20 Mar 2015

An interesting problem providing the sqrt(10) factor.

Massimo Zanetti on 14 Oct 2016

Do you know that "rectangle" is a Matlab function???????????????????????????????????

Jaeho Seol on 18 Oct 2016

The function name 'rectangle' is duplicated with the built-in function. Cannot execute the test trial.

Milan Petrovic on 21 Oct 2016

There was no correct solution since October, 12th, due to a defect in the test.

Milan Petrovic on 24 Oct 2016

Thank you for renaming the function.
The test trials now can be executed correctly.

Brandon Flowers on 4 Dec 2017

great problem

WILMER ALEXANDER TICONA JUAREZ on 7 Aug 2020

function [width, length] = findRectangleDimensions(x)
width =sqrt(x^2/10);
length = 3*width;
end

Solution Comments

Solution 2858573

1 Comment

1 Comment

Ranjeet Nalawade on 20 Aug 2020

good

Solution 1877993

1 Comment

1 Comment

Rudolf Csikja on 18 Jul 2019

Awful wording: longer and shorter side, then width and length.

Solution 1587424

1 Comment

1 Comment

A C on 19 Jul 2018

% x^2 = W^2 + L^2
% L =3*W

Could we solve these equations in matlab?

Solution 1148597

2 Comments

2 Comments

Matthew Jones on 29 Mar 2017

The problem statement should specify which (the width or the height) is the longer side of the rectangle.

David Verrelli on 14 Apr 2017

By convention, length is taken as greater than (or equal) to width if no other information is available. Not sure if the problem statement was rewritten, but currently there's no mention of "height".

Problem Recent Solvers1985

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basic matlab pythagoras

Problem 2019. Dimensions of a rectangle

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Last 200 Solutions

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Problem Recent Solvers1985

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Problem 2019. Dimensions of a rectangle

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Last 200 Solutions

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Problem Recent Solvers1985

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