Given a list of ordered pairs, and the order they should be placed in a line, find the sum of the absolute values of the differences.
list = [1 2
5 3
2 4
order = [1 3 2]
yields: [1 2][2 4][5 3]
or: abs(2-2) + abs(4-5)
or: 0 + 1
or: 1
Solution Stats
Problem Comments
3 Comments
Solution Comments
Show comments
Loading...
Group
Problem Recent Solvers909
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Is Test #3 correct? When I solve it with pencil and paper, I get 15 instead of 14.
[5 4][1 2][2 4][7 5][4 8][4 5][1 6]
= -3 + 0 + 3 + -1 + -4 + -4
= 3+0+3+1+4+4
=15
Have I missed something?
No it's 14. With the ordering, you should get:
[5 4][1 2][2 4][4 8][1 6][4 5][7 5], and the sum is abs(4-1) + abs(2-2) + abs(4-4) + abs(8-1) + abs(6-4) + abs(5-7) = 3 + 0 + 0 + 7 + 2 + 2 = 14
good