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PID output...

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Robert
Robert 2011 年 6 月 20 日
回答済み: rathod ujjval rameshbhai 2016 年 1 月 13 日
Hello all,
I have a questions, how do I clip/bound/limit the output of a PID loop to a certain set of values (say 1000-2000) so all I have to worry about is the tuning?
Regards, Robert

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Paulo Silva
Paulo Silva 2011 年 6 月 20 日
  2 件のコメント
Robert
Robert 2011 年 6 月 20 日
This only works on the input though. My problem is I am putting an error value into the PID loop and I need the output to be between 1000-2000 not -80 to 80 (which is error and current output).. I would prefer not to have to tune the PID specifically to get those bounds. I heard this process is called clipping/bounding/limiting but can't seem to find enough information on it.
Arnaud Miege
Arnaud Miege 2011 年 6 月 22 日
Not necessarily, you can put the saturation block on the output of the PID controller. However, be aware of integrator windup (see my answer).

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その他の回答 (2 件)

Arnaud Miege
Arnaud Miege 2011 年 6 月 20 日
You may also need to add some additional control to prevent integrator windup. The new PID block introduced in R2009b, includes those effects, as well as many more.
Arnaud

rathod ujjval rameshbhai
rathod ujjval rameshbhai 2016 年 1 月 13 日
I am implementing PID controller on the system 1/s......
My question is when I write the command pidtool and get the new window in that there are list of paramenters..... I want to see the output of controller at perticular point i.e. Pout=Kp*e(t)+P0....
other thing is if my system is 1/s then as in step response it becomes 1/s^2 and then Laplace inverse will give output equation.... in case of only P it would be Kp*e(t)*L^-1(1/s).... is it??

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