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Why are the results of the size function different from the whos function Size?

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Brian
Brian 2011 年 6 月 15 日
Why are the results of the size function different from the whos function Size?
Here is an example:
>> excelstring = strfind('ABC DUMP.txt','.xls')
excelstring =
[]
>> size excelstring
ans =
1 11
>> whos excelstring Name Size Bytes Class Attributes
excelstring 0x0 0 double

採用された回答

James Tursa
James Tursa 2011 年 6 月 15 日
Doing this:
size excelstring
Is equivalent to doing this:
size('excelstring')
Whenever you invoke a function without the parens, the remainder of your inputs are taken to be literal string(s).
  1 件のコメント
Matt Fig
Matt Fig 2011 年 6 月 15 日
As described here:
http://www.mathworks.com/help/techdoc/ref/syntax.html
This is called command-function duality.

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その他の回答 (1 件)

the cyclist
the cyclist 2011 年 6 月 15 日
Because the syntax for what you wanted is
>> size(excelstring)
Looks like your syntax is giving the size of the string 'excelstring', rather than that of the variable named excelstring.
  1 件のコメント
Chirag Gupta
Chirag Gupta 2011 年 6 月 15 日
To explain further, size excelstring is equivalent to asking MATLAB to compute size('excelstring').
MATLAB takes the arguments as strings if they are not passed in parenthesis ()

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