Error “Assignment has more non-singleton rhs dimensions than non-singleton subscripts”?

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Why do I get the error “Assignment has more non-singleton rhs dimensions than non-singleton subscripts”?
  3 件のコメント
Walter Roberson
Walter Roberson 2017 年 2 月 23 日
pratik patel:
Please show us
size(X)
size(Y)
size(Z)
size(Vm)
I suspect that you have created either Z or Vm as global variables and failed to initialize them, which would leave them as empty, resulting in an empty right hand side.
Anshu Khare
Anshu Khare 2021 年 1 月 25 日
bankans(i,:)=sum(bsxfun(@times, ft(i,:), H).^2,2);
Assignment has more non-singleton rhs dimensions than non-singleton subscripts
i am getting this error.please help me

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採用された回答

Walter Roberson
Walter Roberson 2013 年 10 月 23 日
編集済み: MathWorks Support Team 2018 年 11 月 27 日
In R2017b and earlier releases, this error occurs when you try to assign to a variable, but the indices of the left- and right-hand side of the assignment are incompatible. For example,
A(1) = [1 2 3];
throws this error because the size of the left-hand side is 1-by-1, but the size of the right-hand side is 1-by-3.
In R2018a and later, there is a new error message that replaces this error:
Unable to perform assignment because the indices on the left side are not compatible with the size of the right side.
For more information on matrix indexing, see:
  3 件のコメント
Adam
Adam 2016 年 7 月 18 日
I imagine it is just a typo.
Walter Roberson
Walter Roberson 2016 年 7 月 18 日
Yes, it was just a typo.

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その他の回答 (1 件)

CHANDRA
CHANDRA 2016 年 8 月 29 日
what is the possible solution for this error
  3 件のコメント
math man
math man 2017 年 9 月 6 日
編集済み: Walter Roberson 2017 年 9 月 7 日
I am getting the same error. But very curiously, if I go to the offending line (with a stop in the debugger), then press play, the error does not occur.
Here is some of the error/code:
Error in RealTime_SpreadOverWrite (line 11)
MainObject.MarketData(Row,SpreadBaseCol)=ViggedProbMat(Row,TextFind('SpreadBase1',RawMarketLabels))*SpreadSignMult;
The relevant values for the operation are all real-scalars which I can see are present when I put a stop before executing this line.
Puzzling- what code can I show to help solve this? Thanks!!
Greg Coyle
Greg Coyle 2017 年 12 月 24 日
Great answer, Walter, thank you. I'd been checking length rather than size and all I needed to do was throw a transpose operator on one variable. Solved!

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