How do I split a color image into its 3 RGB channels?
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Hi,
How can I split a color image into its 3 RGB channels, like in this link:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/150998/image.png)
Thanks
採用された回答
Image Analyst
2017 年 7 月 10 日
You can do that with this code:
% Read in original RGB image.
rgbImage = imread('flower.png');
% Extract color channels.
redChannel = rgbImage(:,:,1); % Red channel
greenChannel = rgbImage(:,:,2); % Green channel
blueChannel = rgbImage(:,:,3); % Blue channel
% Create an all black channel.
allBlack = zeros(size(rgbImage, 1), size(rgbImage, 2), 'uint8');
% Create color versions of the individual color channels.
just_red = cat(3, redChannel, allBlack, allBlack);
just_green = cat(3, allBlack, greenChannel, allBlack);
just_blue = cat(3, allBlack, allBlack, blueChannel);
% Recombine the individual color channels to create the original RGB image again.
recombinedRGBImage = cat(3, redChannel, greenChannel, blueChannel);
% Display them all.
subplot(3, 3, 2);
imshow(rgbImage);
fontSize = 20;
title('Original RGB Image', 'FontSize', fontSize)
subplot(3, 3, 4);
imshow(just_red);
title('Red Channel in Red', 'FontSize', fontSize)
subplot(3, 3, 5);
imshow(just_green)
title('Green Channel in Green', 'FontSize', fontSize)
subplot(3, 3, 6);
imshow(just_blue);
title('Blue Channel in Blue', 'FontSize', fontSize)
subplot(3, 3, 8);
imshow(recombinedRGBImage);
title('Recombined to Form Original RGB Image Again', 'FontSize', fontSize)
% Set up figure properties:
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0, 0, 1, 1]);
% Get rid of tool bar and pulldown menus that are along top of figure.
% set(gcf, 'Toolbar', 'none', 'Menu', 'none');
% Give a name to the title bar.
set(gcf, 'Name', 'Demo by ImageAnalyst', 'NumberTitle', 'Off')
My MATLAB code produces this figure:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/177366/image.png)
which you can see is the same as your example figure you gave:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/177367/image.png)
The original flower image is attached. I cropped it out of your figure.
2 件のコメント
Mahmood Aldhuhl
2020 年 11 月 28 日
hello sir
i try typing the code but show this messgae
Error in Q5 (line 7)
redChannel = rgbImage(:,:,1); % Red channel
DGM
2023 年 2 月 11 日
The only way you'll get an error on that specific line is if rgbImage does not exist. The only way it won't exist is if you didn't create it as the given example does.
その他の回答 (5 件)
sixwwwwww
2013 年 10 月 22 日
If you want to show RGB channels in there original color then you can do like it:
img = imread('filename.png'); % Read image
red = img(:,:,1); % Red channel
green = img(:,:,2); % Green channel
blue = img(:,:,3); % Blue channel
a = zeros(size(img, 1), size(img, 2));
just_red = cat(3, red, a, a);
just_green = cat(3, a, green, a);
just_blue = cat(3, a, a, blue);
back_to_original_img = cat(3, red, green, blue);
figure, imshow(img), title('Original image')
figure, imshow(just_red), title('Red channel')
figure, imshow(just_green), title('Green channel')
figure, imshow(just_blue), title('Blue channel')
figure, imshow(back_to_original_img), title('Back to original image')
I hope it helps. Good luck!
5 件のコメント
Jan
2018 年 3 月 5 日
bassel mar wrote:
Very good and simple code
@bassel mar: Please do not use flags to post a comment, because they are used to inform admins and editors about inappropriate contents like spam or rudeness.
David Sanchez
2013 年 10 月 22 日
my_rgb = my_image;
R = my_rgb(:,:,1);
G = my_rgb(:,:,2);
B = my_rgb(:,:,3);
5 件のコメント
Image Analyst
2020 年 11 月 28 日
An RGB image is like three 2-D monochrome/grayscale images stacked on top of each other in the third dimension. See attached demo for a visualization:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/432813/image.png)
The code basically extracts each 2-D image from the 3-D image into a separate 2-D array. With MATLAB Release 2018b and later, you can use imsplit() instead
[R, G, B] = imsplit(rgbImage);
diya
2016 年 5 月 3 日
how to split rgb image to just take red color and to supress high intensities
1 件のコメント
Image Analyst
2016 年 5 月 3 日
You know how to extract the red channel already
redChannel = rgbImage(:, :, 1);
Now explain what "suppress" means to you. Do you want to set high values to zero? Multiply them by 0.5 or some other number? Apply a gamma curve?
Adam G
2017 年 7 月 12 日
編集済み: Adam G
2017 年 7 月 15 日
I have picture hand.tif.
%the best idea is to make screenshot of this picture
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/177406/image.gif)
I have following codes
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
imfinfo('hand.tif');
[L1]= imread('hand.tif');
figure, imshow(L1);
L1r=L1(:, :, 1);
L1g=L1(:, :, 2);
L1b=L1(:, :, 3);
figure;
imshow(cat(3, L1r, ones(size(L1g)), ones(size(L1b))));
figure;
imshow(cat(3, ones(size(L1r)), L1g, ones(size(L1b))));
figure;
imshow(cat(3, ones(size(L1r)), ones(size(L1g)), L1b));
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
I got following pictures
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/177407/image.gif)
and okay. I have following code
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
imfinfo('hand.tif');
[L1]= imread('hand.tif');
L1=double(L1)/255;
figure, imshow(L1);
L1c=L1(:, :, 1);
L1m=L1(:, :, 2);
L1y=L1(:, :, 3);
figure;
imshow(cat(3, L1c, ones(size(L1m)), ones(size(L1y))));
figure;
imshow(cat(3, ones(size(L1c)), L1m, ones(size(L1y))));
figure;
imshow(cat(3, ones(size(L1c)), ones(size(L1m)), L1y));
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
I got following pictures
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/177408/image.gif)
Is it matlab error or what?
So now I check matrix L1r
L1r=
0 0 0 0 0
0 5 5 3 3
0 5 4 3 4
0 3 4 2 3
0 3 4 2 1
I check matrix L1c
L1c=
0 0 0 0 0
0 0,0196078431372549 0,0196078431372549 0,0117647058823529 0,0117647058823529
0 0,0196078431372549 0,0156862745098039 0,0117647058823529 0,0156862745098039
0 0,0117647058823529 0,0156862745098039 0,00784313725490196 0,0117647058823529
0 0,0117647058823529 0,0156862745098039 0,00784313725490196 0,00392156862745098
Strange when I make L1=double(L1)/255
L1c=L1r/255
cyan=red/255
or matlab error and I got wrong colormap?
???????????? so what color is in matrix L1r and L1c?
I check in Paint Program and I got red color =5 (position of pixel 2,2 ) so L1r should be red, but L1c????
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/177409/image.gif)
6 件のコメント
frishta fro
2020 年 6 月 21 日
who can hehp me to solve that pleeeeeeeeeeees
Write a Matlab program to do the following operations in the attached image.
1- Find the negative of the brain image.
2- Reduce the intensity of Red channel by 80.
3- Increase the intensity of Green channel by 50.
4- Save the output image as a name brain2.jpg. ![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/319747/image.jpeg)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/319747/image.jpeg)
Image Analyst
2020 年 6 月 21 日
- Use imread(), then
- Invert the images using img=255-img
- if image is grayscale, make red, green, and blue equal to the image, otherwise get the red, green, and blue using imsplit()
- Use addition or subtraction to change each color channel
- Combine into color image using cat(3, red, green, blue)
- Write using imwrite()
yazan abusamra
2022 年 12 月 4 日
移動済み: DGM
2023 年 2 月 11 日
hello I have an old photo for my grampa it is rgb but it lookes like gray photo the problem is that the rgb chanels have very close values to each other in all pixels how can I solve this problem and restore the photo so I can see the original color
3 件のコメント
DGM
2022 年 12 月 6 日
移動済み: DGM
2023 年 2 月 11 日
It sounds like a scan/photo of a black & white print or something. If that's the case, the color content is an artifact of the capture method, not the scene content. That would make this a colorization problem, not an adjustment problem.
If it's a faded/degraded color print, there might be adjustment possibilites, but they can easily be limited by the condition and format of the image.
That said, we'd need more information about the images (examples and perhaps an explanation of why they turned gray). I'd be interested, but I agree with Walter.
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