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i have following image in double(i.e range is 0-1) & i want to convert it to 1's and -1's form,just convert 0 to -1.i tried foll code but its not working.please help. :(

1 回表示 (過去 30 日間)
%%just try the foll code:
[d1,d2,d3]=size(img);
for i=1:d1
for j=1:d2
if img(i,j)==0
img(i,j)=-1
end
end
end
%display it and see impixelinfo;
%0 should get converted to -1
%and 1 as it is.
take attached sample img.

回答 (1 件)

David Sanchez
David Sanchez 2013 年 10 月 18 日
I=rgb2gray(rp7);
I2=im2bw(I);
I3 = double(I2);
I3(I2==0) = -1;
  2 件のコメント
Walter Roberson
Walter Roberson 2013 年 10 月 18 日
Or once I3 has been created,
I3 = I3 * 2 - 1;
without using the logical indexing.

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