Plotting a vector field in an annulus

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Avishek Mukherjee
Avishek Mukherjee 2021 年 8 月 9 日
コメント済み: Avishek Mukherjee 2021 年 8 月 9 日
Here is the problem:
Suppose I have an annulus with inner radius 0.71392 and the outer radius 1. I want to plot a vector field on the annulus, where the vectors are unit tangent vectors to the concentric circles within the annulus. Here is the geometry I am talking about:
t=0:0.001:2*pi;
x=cos(t);
y=sin(t);
x1=0.71392*cos(t);
y1=0.71392*sin(t);
x2=cos(t);
y2=sin(t);
plot(x,y,'r',x1,y1,'b',x2,y2,'g');
axis equal
Any suggestion would be greatly appreciated.

採用された回答

KSSV
KSSV 2021 年 8 月 9 日
編集済み: KSSV 2021 年 8 月 9 日
clc; clear all ;
t=0:0.001:2*pi;
x=cos(t);
y=sin(t);
x1=0.71392*cos(t);
y1=0.71392*sin(t);
x2=cos(t);
y2=sin(t);
% Unit tangent vectros
dx1 = gradient(x1) ;
dy1 = gradient(y1) ;
modv1 = sqrt(dx1.^2+dy1.^2) ;
Tx1 = dx1./modv1 ;
Ty1 = dy1./modv1 ;
dx2 = gradient(x2) ;
dy2 = gradient(y2) ;
modv2 = sqrt(dx2.^2+dy2.^2) ;
Tx2 = dx2./modv2 ;
Ty2 = dy2./modv2 ;
plot(x1,y1,'b',x2,y2,'g');
axis equal
hold on
idx = 1:200:length(x1) ;
quiver(x1(idx),y1(idx),Tx1(idx),Ty1(idx),'r')
quiver(x2(idx),y2(idx),Tx2(idx),Ty2(idx),'r')
  5 件のコメント
KSSV
KSSV 2021 年 8 月 9 日
Generate the radii, make circel and follow the same.,
Avishek Mukherjee
Avishek Mukherjee 2021 年 8 月 9 日
@KSSV, I can do it manually. But instead of manually doing it, I created a sequence of radii and created a vector field for each of the radii inside the annulus. The code I implented is this:
t=0:0.001:2*pi;
r = 0.71392:4.5526e-05:1;
x=cos(t);
y=sin(t);
x1=r.*cos(t);
y1=r.*sin(t);
x2=cos(t);
y2=sin(t);
% Unit tangent vectros
dx1 = gradient(x1) ;
dy1 = gradient(y1) ;
modv1 = sqrt(dx1.^2+dy1.^2) ;
Tx1 = dx1./modv1 ;
Ty1 = dy1./modv1 ;
dx2 = gradient(x2) ;
dy2 = gradient(y2) ;
modv2 = sqrt(dx2.^2+dy2.^2) ;
Tx2 = dx2./modv2 ;
Ty2 = dy2./modv2 ;
plot(x1,y1,'b',x2,y2,'g');
axis equal
hold on
idx = 1:200:length(x1) ;
quiver(x1(idx),y1(idx),Tx1(idx),Ty1(idx),'r')
quiver(x2(idx),y2(idx),Tx2(idx),Ty2(idx),'r')
which produces a spiral:

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