storing data in an array from a loop
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Inge
2013 年 10 月 7 日
A1=(1:1:10)*1.22';
A2=(1:1:10)*2.55';
i=1;
for cc=(A1+A2)/2;
G1=[1 2];
G2=[2.6 1.1];
X(i)=(fsolve(@(x)sum(G1.*sin(G2.*x)),cc))'
i = i+1;
end
I think this will work!
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その他の回答 (1 件)
Jan
2013 年 10 月 7 日
The code looks strange. Perhaps you meant:
index = (1:10) * ((1.22 + 2.55) / 2);
G1 = [1 2]; % Move constants out of the loop
G2 = [2.6 1.1];
X = zeros(1, 10);
for k = 1:10
X(k) = fsolve(@(x)sum(G1.*sin(G2.*x)), index(k))';
end
Or perhaps X should be a cell?
X = cell(1, 10);
for k = 1:10
C{k} = ...
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