フィルターのクリア

can anyone help and getting complex roots for nonlinear equation

1 回表示 (過去 30 日間)
vishnu
vishnu 2013 年 10 月 7 日
コメント済み: Walter Roberson 2013 年 10 月 8 日
can any one please solve this non linear equation?it has infinite no of solutions first 3 solutions for each a value i need
x*sin(2*a)+sin(2*x*a)=0
where x is to be find
a=(2*pi-y)/2;
y varies from 0 to 90
please help me
  3 件のコメント
vishnu
vishnu 2013 年 10 月 8 日
they7 have both real and complex solutions for each 'a' value and now i want only complex solutions it may have infinite solutions for just one 'a' value and i want atleast 4 complex solutions for atleast one a value may be take a=45
Walter Roberson
Walter Roberson 2013 年 10 月 8 日
Are you sure that y varies from 0 to 90? It is odd that you would be subtracting a value 0 to 90 from 2*pi . Perhaps y varies from 0 to pi/2 ?

サインインしてコメントする。

回答 (0 件)

カテゴリ

Help Center および File ExchangeSystems of Nonlinear Equations についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by