alternate hist() function

I wanted to know how many times a number is repeated in a vector, so I used the hist() function.

For example, an extracted idea of my code runs like this

a = [1 1 2 3 4];
b=unique(a);        %b=[1 2 3 4]
c=hist(a,b);        %c=[2 1 1 1]
d=find(c~=0);       %d=[1 2 3 4]      %this can be finding with any condition, regarding the repetitition times
result=a(d);        %result=[1 1 2 3] %find the values inside variable a, mathcing the condidiotn above

Looking at b and result variables, I know there are two 1s, and one of 2,3,4 each. I used this way to code the rest

but here is the problem that cost an exception, and I don't know how to get around it, another example that makes an error

a = [4 4];
b=unique(a);        %b=[4]
c=hist(a,b);        %c=[0 0 2 0]        % here i expect the vector to be the length of b like above (1 in this case), but it gives me length of 3
d=find(c~=0);       %d=2      %this can be finding with any condition, regarding the repetitition times
result=a(d);        % error, index exceeding array element

I itentified where the problem is: looks like c=hist(a,b) will output a result with length(c)= length(b)-- if b is a vector with 1+ elements, if b is a scalar then length(c)=b.

This is throwing error in my larger module, and I am not sure how to get around that.

Any smart ideas?

Thanks

Answer 1

[Xingda Chen]

a = [4 4];
b=unique(a);        
c=hist(a,b); 
c=nonzeros(c);      
d=find(c~=0);      
result=a(d);       

I got a simple solution. Closing the question.

PS, Helps a lot to clearly type the problem out. Didn't know what to do before I post this