If loop on lists for counting elements
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I have two lists
A0 = [1,3,5,9];
A1 = [2,5,1,0];
and I want to make counts of how many elements in A0 are smaller than A1. I define:
counter0 = 0;
counter1 = 0;
and then the for loop:
for k=1:length(A0)
if A0(k)>A1(k)
counter0 = counter0 + 1
else if A0(k)<A1(k)
counter1 = counter1 + 1
end
end
end
So the result should had been:
counter0 = 2
counter1 = 2
But this loop will not work for me. How can I make it functional?
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回答 (3 件)
Awais Saeed
2021 年 8 月 5 日
You do not need a loop for this, just use
A0 = [1,3,5,9];
A1 = [2,5,1,0];
count = length(find(A0<A1))
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KSSV
2021 年 8 月 5 日
A0 = [1,3,5,9];
A1 = [2,5,1,0];
iwant = 0 ;
for i = 1:length(A0)
t = nnz(A0(i)<A1) ;
iwant = iwant+t ;
end
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